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natali 33 [55]
3 years ago
14

How many representative particles are in one mole of CO2? PLEASE ANSWER ALMOST DUE

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

I hope this helps, sorry if it doesnt. Not really good with chemistry, hope you have a great day/night :}

Explanation:

A mole (mol) is the amount of a substance that contains 6.02 × 10 23 representative particles of that substance.

12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

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aalyn [17]

Answer:

gravity

Explanation: its a force that pulls you down but you are never making contact with it

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Classify the statements below as Weather or Climate. HELP ME WITH THIS The wind is blowing from the south. The average temperatu
ivanzaharov [21]

Answer:

Weather:

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Explanation:

Hope it helps.

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3 years ago
Advantages and disadvantages of titration?
alisha [4.7K]

Answer:

What are the advantages of titration?

Titrimetric analysis commonly referred to as volumetric analysis offers distinct advantages over cumbersome gravimetric methods:

Speed of analysis.

Instantaneous completion of reactions.

Greater accuracy due to minimization of material loss involved in decanting, filtration, precipitation or similar operations.

Explanation:

Disadvantages

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It requires reactions to occur in a liquid phase, often the chemistry of interest will make this inappropriate.

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<em>hope </em><em>this </em><em>helps </em><em>Plea</em><em>se</em><em> </em><em>inform</em><em> </em><em>me</em><em> </em><em>if</em><em> </em><em>its</em><em> </em><em>help</em><em>ful</em><em> </em>

5 0
3 years ago
Consider the chemical equation in equilibrium.
Andrew [12]
When pressure in a chemical reaction increases, the equilibrium will shift towards the side of the reaction with fewer moles of gas. When there is a decrease in pressure, the equilibrium will shift towards the side of the reaction with more moles of gas.Therefore; in this case; increased the Equilibrium will shift to the left and favor the reverse reaction. This is because the side of products has more moles compared to the side of reactants, thus increased in pressure will aid conversion of products to reactants. 
5 0
4 years ago
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Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?
Step2247 [10]
Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

                               C     +     O2      ------>  CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2. 

                          <u>     86.5 g CO       </u>   = 1.966 moles CO2
                            44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel. 

        1.966 moles CO2   x   <u>   1 mole C   </u>    x   <u>   </u><u>12 g C   </u>  = 23.59 g C
                                             1 mole CO2          1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams. 


            25.0 g - 23.59 g = 1.41 grams Hydrogen 

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen. 

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel, 

Carbon:     <u>  1.966 mol   </u>   = 1.408   x   5 (factor)     = 7
                    1.396 mol

Hydrogen:  <u>  1.396 mol   </u>    = 1.00   x    5 (factor)    = 5
                     1.396 mol

Thus, the empirical formula is C7H5

       
4 0
4 years ago
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