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m_a_m_a [10]
3 years ago
11

Give an example that shows that gravity affects objects through gases liquids and solids

Chemistry
1 answer:
STALIN [3.7K]3 years ago
5 0
Gravity os air so if u let go of something it will fall gravity pulls down things ok
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Adding a neutron to an atom changes what property of the atom?
GrogVix [38]
C, The atomic mass. This could also cause certain elements (i.e. Uranium, Plutonium) to radioactively decay in process called nuclear fission.
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3 years ago
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A baseball player hits a ball. Which is the best description of the energy of the ball as it flies over the pitcher’s head?
Elan Coil [88]

The right option is; b. mechanical

Mechanical energy is the best description of the energy of the ball as it flies over the pitcher’s head.

Mechanical energy is the energy that an object acquires due to its position or due to its motion. From the question, the baseball player has chemical potential energy (stored as food) which is transformed into work. As the baseball player hits the ball, there is energy exchange in which the ball acquires energy to perform its work. The energy obtained by the ball upon which work is done is called mechanical energy.


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3 years ago
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I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
BaLLatris [955]
I really hope this helps I’ve been there too and I’m just doing this so I get the 20 words and I have the picture

8 0
3 years ago
HELP ASAP PLEASE!!!
Dmitry [639]

Answer:

A. Electrolyte

Explanation:

Concentrated sulfuric acid has a density of 1.84 g/millimeter. When you dilute this with water to 5.20 M, you then have a density of 1.30 g/millimeter, which then can be used as a lead storage for batteries in automobiles. (Got help to answer this at Www.wyzant.com

3 0
3 years ago
At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---> +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

4 0
4 years ago
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