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Rudiy27
3 years ago
6

When a bicycle tire gets mud on it, the tire becomes slippery. What does the mud do to the tire? A. Increases the force of gravi

ty B. Increases the force of friction C. It decreases the force of friction D. It decreases the force of gravity
Physics
2 answers:
larisa86 [58]3 years ago
8 0
Question: <span>When a bicycle tire gets mud on it, the tire becomes slippery. What does the mud do to the tire?

C. It decreases the force of friction.

First mud is not a solid. It is more of a slow liquid like corn syrup. And when you are caught in mud or trying to ride past the mud you loose friction with the ground.
You could also resemble friction with traction. In a car. If there is water & oil mixed on the road and you go past it at a high mph range. You will loose traction and start skipping against the mixed substance. This reduces your traction (friction) with the ground.

Final Answer:

C. It decreases the force of friction
</span>
Flura [38]3 years ago
7 0
The answer to this is C.
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Why are there multiple versions of the scientific method?
gavmur [86]

Answer:

it's because some versions have more steps and others have less

4 0
3 years ago
What gravitational force does the earth exert on a person
lara [203]

The  gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.

<h3>What is the gravitational force of the earth on the person?</h3>

The gravitational force exerted by the earth on a person standing on the earth's surface is given below as follows:

  • F = \frac{Gm^{1}m^{2}}{r^{2}}

where

G = 6.67 * 10⁻¹¹

m¹ = 62 kg

m² = 5.97 * 10²⁷ kg

r = 6.4 * 10⁶ m

F = \frac{5.97*10^{24}*62*6.67*10^{-11}}{(6.4*10^{6}){2}} = 602.74\:N

Therefore, the gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.

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7 0
2 years ago
The maximum height a typical person can jump is about 60cm (0.6m). By how much does the gravitational potential energy increase
sasho [114]

The gravitational potential energy will increase by 423.36 J

<h3>How to determine the potential energy at ground level</h3>
  • Mass (m) = 72 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) = 0 m
  • Potential energy at ground level (PE₁) =?

PE = mgh

PE₁ = 72 × 9.8 × 0

PE₁ = 0 J

<h3>How to determine the potential energy at 60 cm (0.6 m)</h3>
  • Mass (m) = 72 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) = 0.6 m
  • Potential energy at 60 cm (0.6 m) (PE₂) =?

PE = mgh

PE₂ = 72 × 9.8 × 0.6

PE₂= 423.36 J

<h3>How to determine the change in potential energy </h3>
  • Potential energy at ground level (PE₁) = 0 J
  • Potential energy at 60 cm (0.6 m) (PE₂) = 423.36 J
  • Change in potential energy =?

Change in potential energy = PE₂ - PE₁

Change in potential energy = 423.36 - 0

Change in potential energy = 423.36 J

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8 0
2 years ago
The Orion nebula is one of the brightest diffuse nebulae in the sky (look for it in the winter, just below the three bright star
Oxana [17]

Answer:

T=183.21K

Explanation:

We have to take into account that the system is a ideal gas. Hence, we have the expression

PV=nRT

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.

Thus, it is necessary to calculate n and V

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V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi (5.9*10^{15}m)^3=8.602*10^{47}m^3

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Hence, we have (1 Pa = 9.85*10^{-9}atm)

T=\frac{PV}{nR}=\frac{(6.8*10^{-9}*9.85*10^{-6}atm)(8.86*10^{50}L)}{(0.0820\frac{atm*L}{mol*K})(3.95*10^{36}mol)}\\\\T=183.21K

hope this helps!!

8 0
3 years ago
A bird flies due north with a speed of 15 m/s relative to the air. The air moves due west with a speed of 11 m/s relative to the
Aleksandr [31]

Answer:

I'm not sure if the directions affect the speed tho

but I think it's 4? cause it's the speed relative to the ground

hope this helps:))

4 0
3 years ago
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