Answer:
48 meters north
Explanation:
If you measure the distance between the point Marus started and the point where they stopped after traveling 1,250 meters back south, you get 48 meters. To make this a displacement quantity, you add 'north' to the end and get 48 meters north, considering this was the initial direction of the motorcycle.
Answer:
Temperature of parcel at 1000 ft is 85.5°F
Explanation:
Temperature of parcel at 0 ft =T₁ = 91.0°F
Dry adiabatic rate = 5.5°F/100 ft
Temperature of parcel at H₂ (1000 ft) = T₂ =?
Height of LCL = 5000 ft
As (1000<5000), so using the formula for parcel below or at the LCL i.e.
The answer is b) venus because the period rotation is also referred to as a day so if venus’ period of rotation is 243 [earth] days and its year is 225 [earth] days, then the period of rotation is longer.
(a) The time for the capacitor to loose half its charge is 2.2 ms.
(b) The time for the capacitor to loose half its energy is 1.59 ms.
<h3>
Time taken to loose half of its charge</h3>
q(t) = q₀e-^(t/RC)
q(t)/q₀ = e-^(t/RC)
0.5q₀/q₀ = e-^(t/RC)
0.5 = e-^(t/RC)
1/2 = e-^(t/RC)
t/RC = ln(2)
t = RC x ln(2)
t = (12 x 10⁻⁶ x 265) x ln(2)
t = 2.2 x 10⁻³ s
t = 2.2 ms
<h3>
Time taken to loose half of its stored energy</h3>
U(t) = Ue-^(t/RC)
U = ¹/₂Q²/C
(Ue-^(t/RC))²/2C = Q₀²/2Ce
e^(2t/RC) = e
2t/RC = 1
t = RC/2
t = (265 x 12 x 10⁻⁶)/2
t = 1.59 x 10⁻³ s
t = 1.59 ms
Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.
Learn more about energy stored in capacitor here: brainly.com/question/14811408
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