Two spheres are cut from a certain uniform rock. One has radius 4.10 cm. The mass of the other is eight times greater.
1 answer:
Answer:
8.2 cm
Explanation:
mass of one sphere = m
mass of other sphere = 8 m
Radius of first sphere = r = 4.10 cm
let the radius of another sphere is R
As we know that mass = volume x density
Let the density of the rock is d.
density of rock remains same.
density of small sphere = density of big sphere
mass of small sphere / volume of small sphere =
mass of big sphere / volume of big sphere
R = 2 r
R = 2 x 4.10 = 8.2 cm
Thus, the radius of big sphere is 8.20 cm.
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Answer:
The horizontal component of the velocity is 188 m/s
The vertical component of the velocity is 50 m/s.
Explanation:
Hi there!
Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:
We can find vx using the following trigonometric rule of a right triangle:
cos α = adjacent / hypotenuse
cos 15° = vx / 195 m/s
195 m/s · cos 15° = vx
vx = 188 m/s
The horizontal component of the velocity is 188 m/s
To calculate the y-component we will use the following trigonometric rule:
sin α = opposite / hypotenuse
sin 15° = vy / 195 m/s
195 m/s · sin 15° = vy
vy = 50 m/s
The vertical component of the velocity is 50 m/s.
Complete Question:
When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.
Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?
Answer:
ΔE = 1.224 * 10⁻²² J
Explanation:
In the 6f state, the orbital quantum number, L = 3
The magnetic quantum number,
The change in energy due to Zeeman effect is given by:
Magnetic field B = 2.02 T
Bohr magnetron,
ΔE = 1.224 * 10⁻²² J