According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.
<h3>How to calculate the amount of solute that precipitates out of solution?</h3>
To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:
- Quantity of solute at 80°C: 170 grams.
- Quantity of solute at 20°C: 40 grams.
- 170 grams - 40 grams = 130 grams
According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.
Note: This question is incomplete because the graph is missing. Here is the graph
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Answer:
c.
Explanation:
not to positive but I hope this is correct ♀️
The number of molecules involved in the reaction, in this case, the number of Ag atoms involved.
Answer:
2.042 g
Explanation:
The reaction that takes place is:
- 2HCl + Mg(OH)₂ → Mg²⁺ + 2Cl⁻ + 2H₂O
First we <u>calculate how many HCl moles were added</u>, using <em>the given volume and concentration</em>:
- 30 mL ⇒ 30 / 1000 = 0.030 L
- 5.6 M * 0.030 L = 0.168 mol HCl
Then we<u> convert HCl moles into Mg²⁺ moles</u>, using the<em> stoichiometric coefficients</em>:
- 0.168 mol HCl *
= 0.084 mol Mg⁺²
Finally we <u>convert Mg moles into grams</u>, using its<em> molar mass</em>:
- 0.084 mol Mg⁺² * 24.305 g/mol = 2.042 g