1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexus [3.1K]
3 years ago
12

6.02 x 109 = hellllppppppppppppppppppppppppppppppppppppppppppppppppppppp

Chemistry
2 answers:
worty [1.4K]3 years ago
6 0
=656.18 thts what you get if you know math  hahah 


mojhsa [17]3 years ago
5 0
The answer is 656.18
6.02 x 109 = 656.18
You might be interested in
What does it mean for energy to be conserved
marysya [2.9K]

Answer: It means that the energy is being stored or preserved to be used at a later time.

Your question was a little vague, so if this isn't the answer you were looking for, just let me know and I'll fix it.

Hope this helps! Good luck! :D

6 0
3 years ago
How many moles (of molecules or formula units) are in each sample? 79.34 g cf2cl2?
Alona [7]
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of fluorine = 18.99 grams
molecular mass of chlorine = 35.5 grams
Therefore:
one mole of CF2Cl2 = 12 + 2(18.99) + 2(35.5) = 120.98 grams
Therefore, we can use cross multiplication to find the number of moles in 79.34 grams as follows:
mass = (79.34 x 1) / 120.98 = 0.6558 moles

Now, one mole contains 6.022 x 10^23 molecules, therefore:
number of molecules in 0.65548 moles = 0.6558 x 6.022 x 10^23
                                                              = 3.949 x 10^23 molecules
7 0
3 years ago
A sample of gold has a mass of 67.2 g and a volume of 3.5 cm3. the density of gold is
scoray [572]
67.2g/3.5cm3= 19.2g/cm3
6 0
3 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 163 mL of coffee at 97.9°C so that the r
Stolb23 [73]

Answer:

248 mL

Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by water (Qw) and the heat released by the coffee (Qc) is zero.

Qw + Qc = 0

Qw = -Qc [1]

We can calculate each heat using the following expression.

Q = c × m × ΔT

where,

  • c: specific heat
  • m: mass
  • ΔT: change in the temperature

163 mL of coffee with a density of 0.997 g/mL have a mass of:

163 mL × 0.997 g/mL = 163 g

From [1]

Qw = -Qc

cw × mw × ΔTw = -cc × mc × ΔTc

mw × ΔTw = -mc × ΔTc

mw × (54.0°C-25.0°C) = -163 g × (54.0°C-97.9°C)

mw × 29.0°C = 163 g × 43.9°C

mw = 247 g

The volume corresponding to 247 g of water is:

247 g × (1 mL/0.997 g) = 248 mL

8 0
3 years ago
Which of the following isotopes is NOT considered to be a major threat to human health from nuclear fallout? a. strontium-90 b.
Nat2105 [25]
Ohhh it’s A) strontium
4 0
3 years ago
Other questions:
  • Use bond energies to calculate δhrxn for the reaction. n2(g)+3cl2(g)→2ncl3(g)
    9·2 answers
  • Bruce left some butter out in his kitchen. Bright sunlight came in through the window and melted the butter. Heat energy from th
    12·2 answers
  • On the basis of the solubility curves shown above, the greatest percentage of which compound can be recovered by cooling a satur
    8·2 answers
  • What is the gram-formula mass of Fe(NO3)3?
    14·2 answers
  • A 3.00 g mass of compound x was added to 50.0 g of water and it is found that the freezing point has decreased by 1.25 degrees c
    7·1 answer
  • The answer to this question
    12·1 answer
  •  A substance has 55.80% carbon, 7.04% Hydrogen, and 37.16% Oxygen. What is it's empirical and molecular formula if it has a mola
    13·2 answers
  • The composition (in mole percent) of the atmosphere is 78.1% N2, 21.0% O2, and 0.9% Ar. What is the partial pressure of each gas
    9·1 answer
  • calculate the mols of alt gas if the volume is 0.97 liters at a temperature of 12 C and the pressure is 152 Kpa’s
    11·1 answer
  • This element inthe 5th period wants to gain one electron to make an ionic bond.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!