A parallel-plate capacitor has an area of

An object of mass 82kg is accelerated upward at 3.2m/s/s. what force is required

vampirchik [111]

F = m · a

In order to accelerate 82 kg upward at the rate of 3.2 m/s², a NET upward force of (82kg · 3.2m/s²) = 262.4 Newtons is required.

But if the object is on or near the surface of the Earth, then there's a downward force of (82kg · 9.8m/s²) = 803.6 N already acting on it because of gravity.

So you need to apply (803.6N + 262.4N) = <em>1,066 Newtons UPward</em>, in order to cancel its own weight and accelerate it upward at that rate.

6 0

4 years ago

Calculate the average speed of an automobile that travels 60km east and then 80km north in two hours

lbvjy [14]

We need to calculate speed , so we don't need to consider direction.
speed =distance/time
=(80+60)/2
=70.

But if we were to calculate velocity,we would need to consider the direction.
The direction of resultant displacement would be in north east direction with displacement
=√60^2 +80^2
=100km

The average velocity=100/2=50kmph

8 0

3 years ago

"In this lesson, you learned about renewable energy resources and nonrenewable energy resources. Think about the resources discu

Nutka1998 [239]

U can also add solar energy and hydro energy. Solar energy is by using the sun, while hydro is by using the force of water.
This is how hydro energy works:
its is usually built near a waterfall, OK so when the water falls of the cliff of the water fall , it creates a force which helps turn the generator and then it is carried into poles of electricity.
Hope this helps plus i gave u extra point Good luck :)

5 0

3 years ago

Suppose that the voltage across the resistor is held constant at 40 volts. If the resistance is steadily decreasing at a rate of

hjlf

Answer:

The current is increasing at a rate of 0.32 ampere per second.

Explanation:

The voltage of the resistor is modelled after Ohm's Law, which states that voltage is directly proportional to current:

$V = i\cdot R$ (1)

Where:

$V$ - Voltage, measured in volts.

$i$ - Current, measured in amperes.

$R$ - Resistance, measured in ohms.

An expression for the rate of change in voltage is found by Differential Calculus:

$\frac{dV}{dt} = \frac{di}{dt}\cdot R +i\cdot \frac{dR}{dt}$

$\frac{dV}{dt} = \frac{di}{dt}\cdot R + \frac{V}{R}\cdot \frac{dR}{dt}$ (2)

Where:

$\frac{dV}{dt}$ - Rate of change in voltage, measured in volts per second.

$\frac{di}{dt}$ - Rate of change in current, measured in amperes per second.

$\frac{dR}{dt}$ - Rate of change in resistance, measured in ohms per second.

If we know that $\frac{dV}{dt} = 0\,\frac{V}{s}$ , $R = 5\,\Omega$ , $V = 40\,\Omega$ and $\frac{dR}{dt} = -0.2\,\frac{\Omega}{s}$ , then the rate of change in current is: