Answer:
388.97 nm
Explanation:
The computation of the wavelength of this light in benzene is shown below:
As we know that
n (water) = 1.333
n (benzene) = 1.501

And, the wavelength of water is 438 nm
![\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}]](https://tex.z-dn.net/?f=%5Clambda%20%28benzene%29%20%3D%20%5Clambda%20%28water%29%20%5B%5Cfrac%7Bn%28water%29%7D%7Bn%28benzene%7D%5D)
Now placing these values to the above formula
So,

= 388.97 nm
We simply applied the above formula so that we can easily determine the wavelength of this light in benzene could come
Answer:
8.854 pF
Explanation:
side of plate = 0.1 m ,
d = 1 cm = 0.01 m,
V = 5 kV = 5000 V
V' = 1 kV = 1000 V
Let K be the dielectric constant.
So, V' = V / K
K = V / V' = 5000 / 1000 = 5
C = ε0 A / d = 8.854 x 10^-12 x 0.1 x 0.1 / 0.01 = 8.854 x 10^-12 F
C = 8.854 pF
Answer:
Fₓ = 0,
= 0 and
<em> = - 3.115 10⁻¹⁵ N</em>
Explanation:
The magnetic force given by the expression
F = q v xB
the bold are vectors, the easiest analytical way to determine this force in solving the determinant
F = 1.6 10⁻¹⁵ [ i( 0-0) + j (0-0) + k^( 5.8 0.60 - 0.81 67) ]
F =i^0 + j^0
- k^ 3.115 10⁻¹⁵ N
Fₓ = 0
= 0
<em> = - 3.115 10⁻¹⁵ N</em>
Answer:
536.56 m/s
Explanation:
We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:
Mass (m) of Porsche = 1361 kg
Velocity (v) of Porsche = 26.82 m/s
Momentum of Porsche =?
Momentum = mass × velocity
Momentum = 1361 × 26.82
Momentum of Porsche = 36502.02 Kgm/s
Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:
Your Mass = 68.03 kg
Your Momentum = Momentum of Porsche = 36502.02 Kgm/s
Your velocity =?
Momentum = mass × velocity
36502.02 = 68.03 × velocity
Divide both side by 68.03
Velocity = 36502.02 / 68.03
Velocity = 536.56 m/s
Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.
Answer:
The total frictional force is 358.0 newtons
Explanation:
Power is the amount of average work (W) an object does on a period of time (Δt):

Remember average work is average force (F) times displacement (Δs):

but displacement over time is average speed
, then:
(1)
That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308
=
, then:
