For a molecule AB2, 3.5g of A represents one molar fraction, and 8.00g B represents 2 molar fractions (or 4.0+4.0). Therefore, a direct ratio can be given as 3.5:4.0, or 1:1.14. This means a molecule AnBm will give a mass ratio for A:B of n:1.14xm
For a molecule AB, for every 1g of A, you will have 1.14g of B.
For a molecule AB2, for every 1g of A, you will have 2.28g of B.
For a molecule A2B3, for every 1g of A, you will have (1.14x3/2) 1.71g of B.
Answer:
The dog should be given half of 100 mg tablet in the morning and another half of 100 mg tablet in an evening.
Explanation:
Weight of the dog = 50 pounds = 22.68 kg
1 kg = 2.205 pounds
Amount of daily dose prescribed by doctor = 4.4 mg/kg
Total mount of dose = 4.4 mg/kg × 22.68 kg = 99.79 mg
99.79 mg ≈ 100 mg
49.89 mg ≈ 50 mg
So, according to doctor prescription dog should be given half 100 mg tablet in the morning and another half of 100 mg tablet in an evening.
Answer:
[H⁺] = 0.00013 M
[OH⁻] = 7.7 × 10⁻¹¹ M
Explanation:
Step 1: Calculate the concentration of H⁺ ions
HCl is a strong acid that dissociates according to the following equation.
HCl ⇒ H⁺ + Cl⁻
The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.
Step 2: Calculate the concentration of OH⁻ ions
We will use the ionic product of water equation.
Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]
[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M
For this question, you must know that there are 6.022e23 atoms/molecules per mole of any substance (this is Avogadro's number). Therefore, your answer is 6.022e23 * 1.60 = 9.64e23 molecules of sulfur dioxide. (the "e" represents "times ten to the power of ___ ")
Answer : The mass of 
required is 18.238 grams.
Explanation : Given,
Mass of 
= 83.10 g
Molar mass of = 146 g/mole
Molar mass of = 256.52 g/mole
The balanced chemical reaction is,
First we have to determine the moles of .
Now we have to determine the moles of .
From the balanced chemical reaction we conclude that,
As, 8 moles of produced from 1 mole of
So, 0.569 moles of produced from 
mole of
Now we have to determine the mass of .
Therefore, the mass of required is 18.238 grams.
