We can achieve equilibrium state, when the concentration of product and reactants are equal to each other.
<h3>Describe this system when it reaches phase equilibrium?</h3>
In this type of system, when the same amount of liquid water is converted into gaseous form of water and the gaseous form of water into liquid form of water. This phase is known as equilibrium phase or state because same amount of reactants and products are produced .
So we can conclude that we can achieve equilibrium state, when the concentration of product and reactants are equal to each other.
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Answer:
The balanced equations for the reactions are outlined below:
Explanation:
A balanced equation describes how many (number of moles) atoms of the reactant give rise to how many (number of moles) of product.
- Hydrogen sulfide gas () and oxygen gas () react to produce sulfur dioxide gas () and water vapor gas.
- The balanced equation for the reaction, taking into consideration the states is:
→
Vanadium(II) oxide (VO) is oxidized by iron(III) oxide (Fe2O3) resulting in the formation of vanadium(V) oxide (V2O5) and iron(II) oxide (FeO).
The balanced equation:
→
Answer:
The incorrect statement is option B and D.
Explanation:
Carbohydrates are more generally is known as the sugars that are composed of the carbon, hydrogen and oxygen atoms. Monosaccharides are the single unit of carbohydrates while disaccharides are the sugars that contain two molecules of the sugar and similarly saccharides with multiple sugars are called polysaccharides. The general chemical formula of the carbohydrates Cn(H2O)n, however the complex sugars does not follow this formula. Amino sugars are contains NH2 in their formula so carbohydrates not necessarily contains only H, O, AND C always.
Thus, the incorrect answer is - option B and D.
Answer:
Explanation: A compound with the empirical formula SO has a molecular weight of 96.13
Answer:
5.20 grams of Br₂
Explanation:
From our previous knowledge;
We understand that:
The number of moles of a given element = mass of the element divided by its molar mass.
Mathematically:
From the given information, let's assume that the 0.065 moles of liquid -bromine partake in the reaction.
From the periodic table, the molar mass of Bromine is = 79.9 g/mol
As such, the mass of liquid that partakes is calculated as:
0.065 mol = mass/ 79.9 g/mol
mass = 0.065 mol × 79.9 g/mol
mass of liquid that partakes in the reaction = 5.20 grams of Br₂