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ZanzabumX [31]
3 years ago
9

(a) Explain why a stainless steel containing 18wt % Cr is magnetic and is often used for knife blades, while a stainless steel c

ontaining 18 wt % Cr and 8 wt% Ni is not magnetic and is often used for stainless steel parts that need to be forged. (Pure Ni has an f.c.c. structure.)(b)Mo, W, and V all readily form small stable carbides. Explain why these elements can be used to produce tool steels thatretain their hardness at temperatures well above the temperature at which martensite would become over-tempered.(c)* A teaspoon is made of a single piece of stainless steel containing nickel. It is observed that the bowl of the spoon is not magnetic, but the handle is. Assume that all parts of the spoon are always at the same temperature, and that plastic deformation is used to form both the bowl and the handle. Explain the difference in properties(why is the crystal structure different).
Engineering
1 answer:
lozanna [386]3 years ago
5 0

Answer:

A stainless steel containing 18wt% of Chromium are magnetic and often used for knifes and blade because of the lattice structure of the stainless steel. The stainless steel are hard, due to the molecules in chromium are smaller and which makes them look like the molecules in wrought iron.

A stainless steel which contains 18wt%Cr and 8wt%Ni are not magnetic because of the lattice structure of the metal stainless steel. This steel are not very hard, due to the molecules of larger and looks like the molecules of a cast iron.

Tool steel that are mixed with small stable carbide retains their temperature when heated above the the normal temperature that can melt steel, because the steel has been mixed with carbide. Carbide is rich in carbon, and has a very high temperature which makes it able to retain heat. When carbides mixes with metal, it boiling point increase to a very high temperature.

The teaspoon that is made up of a single piece of stainless steel that contains only Nickel is made of two parts, the handle and the bowl. The bowl part are not magnetic because it is curved and very smooth, which changes the lattice structure of that part to become FCC. The handle part are magnetic because they are plain and are not very smooth, which makes the lattice structure to be BCC.

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Steam enters a turbine at 8000 kPa, 440oC. At the exit, the pressure and quality are 150 kPa and 0.19, respectively.
levacccp [35]

Answer:

\dot W_{out} = 3863.98\,kW

Explanation:

The turbine at steady-state is modelled after the First Law of Thermodynamics:

-\dot Q_{out} -\dot W_{out} + \dot m \cdot (h_{in}-h_{out}) = 0

The specific enthalpies at inlet and outlet are, respectively:

Inlet (Superheated Steam)

h_{in} = 3353.1\,\frac{kJ}{kg}

Outlet (Liquid-Vapor Mixture)

h_{out} = 890.1\,\frac{kJ}{kg}

The power produced by the turbine is:

\dot W_{out}=-\dot Q_{out} + \dot m \cdot (h_{in}-h_{out})

\dot W_{out} = -2.93\,kW + (1.57\,\frac{kg}{s} )\cdot (3353.1\,\frac{kJ}{kg} - 890.1\,\frac{kJ}{kg} )

\dot W_{out} = 3863.98\,kW

8 0
3 years ago
Which is not an affect of alcohol
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3 years ago
A cantilever timber beam with a span of L = 4.25 m supports a linearly distributed load with maximum intensity of w0 = 5.5 kN/m.
9966 [12]

Answer:

the minimum width is b= 0.1414m = 141mm

Explanation:

]given,

L= 4.25

w₀ = 5.5kN/m,

allowable bending stress = 7MPa

allowable shear stress = 875kPa

h/b = 0.67

b = ?

for a linearly distributed load, with maximum load intensity, w₀ of 5.5kN/m,

the maximum moment, M exerted by the timber is =  \frac{w₀ L²}{9√3}[/texM = w₀ L²}/{9√3 = 99.34/15.6 =6.367kNmfor a linearly distributed load, with maximum load intensity, w₀ of 5.5kN/m, the shear force, V =  [tex]\frac{w₀ L}{2}[/texV = {w₀ L}/{3} = 7.79kNfor maximum bending stress of a rectangular timber, B, = [tex]\frac{6M}{bh²}

given h/b = 0.67, i.e h=0.67b

allowable bending stress = \frac{6M}{bh²} = 7000kPa

7000  = (6*6.37)/ (b *(0.67b)² ) = 38.21/0.449b³

3080b³=38.21

b³ = 38.21/3080 = 0.0124

b = 0.232m

h=0.67b = 0.67* 0.232 = 0.155m

for allowable  shear stress = (3V)/(2bh)

875 = (3V)/(2bh) = (3x 7.79)/(2xbx0.67b)

875 = 23.375/1.34b²

1172.5 b²= 23.375

b² =0.0199

b= 0.1414m

h=0.67b = 0.67* 0.1414 = 0.095m

the minimum width is b= 0.1414m = 141mm

4 0
3 years ago
Which of the following types of valves have a valve stem that moves up and down in a valve guide? Select one: a. Poppet valves b
Alja [10]

Answer:c

Explanation:

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5 0
3 years ago
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You plan to install an active, liquid-based solar heating system for hot water. There are four candidate collector systems. Your
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Solution:

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y=F_{R}(\tau \alpha)_{n} x \frac{F_{R}^{\prime}}{F_{R}} \times \frac{(\bar{\tau} d)}{(T d)_{n}} \times \bar{H}_{T} N \times \frac{A C}{L}

\frac{x}{y}=\frac{ u_{L} \times\left(T_{x t}-\bar{T}_{a}\right) \times \Delta t}{\left(\tau_{x}\right)_{h} \times\left(\frac{\bar{\tau}_{d}}{\left.| \tau_{d}\right)_{n}}\right) \times \bar{H}+N}

From the table,

1) \(\quad x=2 \cdot 87, \quad y=0.96\)\\\(\frac{x}{y}=\frac{2187}{0.96}\)22895\\\\2) \(x=3 \cdot 466 \cdot y=6 \cdot 998\)\\\(\frac{x}{y}=\frac{3 \cdot 466}{0.898}\)\(=3 \cdot 4729\)

3\(x=3 \cdot 229, y=1 \cdot 08\)\\\(\frac{x}{x}=\frac{3 \cdot 229}{1 \cdot 08}\)\\=2.9898\)\\\\4) \(x=6.525, y=1.094\)\\\(\frac{x}{y}=\frac{5.625}{1.094}\)\\=5.0502

8 0
4 years ago
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