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4 years ago

How does the kinetic energy of a substance's particles in the gas phase compare to their kinetic energy in the solid phase?

2 answers:

Colt1911 [192]4 years ago

8 0

The kinetic energy of a substance's particles in the liquid phase compare to their kinetic energy in the gas phase in a way that the particles have less kinetic energy in the liquid phase than they do in the gas phase.

postnew [5]4 years ago

4 0

In the gas phase the particles move fast while in the solid phase they cant move

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What's your favorite show mines riverdale and glee also who's your crush teehee

Dominik [7]

Answer:

Obviously sponge bob come on!

Explanation:

He's amazing.

and part 2 is a secret lol

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4 years ago

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A particular oral contraceptive contains 0.038 mg of ethinyl estradiol in each pill. The formula of this compound is C20H24O2. H

Ray Of Light [21]

Answer: The number of molecules of ethinyl estradiol present in one pill are $7.71\times 10^{16}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethinyl estradiol = 0.038 mg = $3.8\times 10^-5}g$ (Conversion factor: 1 g = 1000 mg)

Molar mass of ethinyl estradiol $(C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol$

Putting values in above equation, we get:

$\text{Moles of ethinyl estradiol}=\frac{3.8\times 10^{-5}g}{296g/mol}=1.28\times 10^{-7}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, $1.28\times 10^{-7}mol$ of ethinyl estradiol will contain = $(1.28\times 10^{-7}\times 6.022\times 10^{23})=7.71\times 10^{16}$ number of molecules

Hence, the number of molecules of ethinyl estradiol present in one pill are $7.71\times 10^{16}$

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3 years ago

How many carbon atoms are in 6 molecules of carbon dioxide?

o-na [289]

For CO2 there is one atom of carbon and two atoms of oxygen. For H2O, there is one atom of oxyegen and two atoms of hydrogen. A moleclue can Be made of only one type of atom

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3 years ago

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9.Out of the following which is a poly atomic molecule. (H2, CI 2.03.)

Vikki [24]

the poly atomic molecule is H2

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3 years ago

0.448 g of an unknown diprotic acid is dissolved in about 60 mL of water in a beaker. The solution is transferred to a 100.00 mL

liq [111]

According to the Question:

We initially had 0.448 grams of the unknown diprotic acid, which was added to about 60 mL of water and that solution was added to a 100 mL flask and filled to the 100 mL mark

The above is as mentioned in the question, our 0.448 grams of diprotic acid is basically diluted to 100 mL [it's volume has been increased to 100mL]

but the amount of the acid is still the same

Which means that we now have 0.448 grams of the diprotic acid in a 100mL solution

Percent of the diprotic acid that will be present in the Erlenmeyer Flask:

From this 100 mL solution, 25 mL is transferred to the Erlenmeyer Flask

Which means that (25/100) * 100 = 25 % of the 0.448 grams of diprotic acid is present in the 25 mL sample

Mass of di-protic acid in the 25 mL solution:

Since 25% of the initial amount remains in the final solution,

Mass of the diprotic acid in the final solution = 0.448 * 0.25

Mass in the final solution = 0.112 grams

Therefore, 0.112 grams of the di-protic acid will be present in the Erlenmeyer Flask

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3 years ago