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larisa86 [58]
2 years ago
12

Each step in any energy conversion process will _____. gain energy create energy dissipate energy destroy energy

Physics
2 answers:
Damm [24]2 years ago
7 0
The correct answer is to dissipate energy. Each step in any energy conversion process will dissipate energy. The energy conversion is the process in which a form of energy is being converted into a new or another form of energy.
fomenos2 years ago
7 0

The correct answer to the question is : Energy dissipate.

EXPLANATION:

Before coming into any conclusion, first we have to understand law of conservation of energy.

As per law of conservation of energy, energy can neither be created nor be destroyed. It can only change from one form to another form, and the total energy of the universe is always constant.

As per the question, there is energy conversion. One form of any energy may be converted into various types of energy. One particular type of energy is not obtained always.

Hence, the correct answer to the question is energy is dissipated during energy conversion.

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4 0
3 years ago
A source at rest emits light of wavelength 500 nm. When it is moving at 0.90c toward an observer, the observer detects light of
Vesna [10]

Answer:

The observer detects light of wavelength is 115 nm.

(b) is correct option

Explanation:

Given that,

Wavelength of source = 500 nm

Velocity = 0.90 c

We need to calculate the wavelength of observer

Using Doppler effect

\lambda_{o}=\sqrt{\dfrac{1-\beta}{1+\beta}}\lambda_{s}

Where, \beta=\dfrac{c}{v}

\lambda_{o}=\sqrt{\dfrac{c-0.90c}{c+0.90c}}\times500\times10^{-9}

\lambda_{o}=115\ nm

Hence, The observer detects light of wavelength is 115 nm.

8 0
3 years ago
Two identical strings, of identical lengths of 2.00 m and linear mass density of μ=0.0065kg/m, are fixed on both ends. String A
kolezko [41]

Answer:

beat frequency = 13.87 Hz

Explanation:

given data

lengths l = 2.00 m

linear mass density μ = 0.0065 kg/m

String A is under a tension T1 = 120.00 N

String B is under a tension T2 = 130.00 N

n = 10 mode

to find out

beat frequency

solution

we know here that length L is

L = n × \frac{ \lambda }{2}      ........1

so  λ = \frac{2L}{10}  

and velocity is express as

V = \sqrt{\frac{T}{\mu } }    .................2

so

frequency for string A = f1 = \frac{V1}{\lambda}

f1 = \frac{\sqrt{\frac{T}{\mu } }}{\frac{2L}{10}}

f1 = \frac{10}{2L} \sqrt{\frac{T1}{\mu } }      

and

f2 = \frac{10}{2L} \sqrt{\frac{T2}{\mu } }

so

beat frequency is = f2 - f1

put here value

beat frequency = \frac{10}{2*2} \sqrt{\frac{130}{0.0065}}  - \frac{10}{2*2} \sqrt{\frac{120}{0.0065} }

beat frequency = 13.87 Hz

6 0
3 years ago
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