An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin as h
2 answers:
Answer:
He has done a work of 50 J on the javelin.
Explanation:
The work can be defined as:
(1)
Where W is the work, d is the distance and is the angle between the force and the direction of the displacement.
For this particular case the force has the same direction of the displacement, so
Then, replacing all the values in equation 1 it is gotten:
But 1J = , therefore:
Hence, he has done a work of 50 J on the javelin.
Key term:
1J = 1 Joule
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