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Mice21 [21]
3 years ago
11

How long does it take for mars to rotate on its axis

Physics
2 answers:
Svetllana [295]3 years ago
8 0

Hello There!

It takes the planet Mars around 24 hours, 37 minutes, 23 seconds to rotate on its axis. This is around the same amount of time that it takes our planet to rotate once on its axis.

ratelena [41]3 years ago
3 0
Answer: 26.4 hours
Explanation: The axis of Mars is tilted at 25 degrees and 12 minutes relative to its orbital plane about the Sun. This produces seasons on the surface of Mars, similar to the seasons on Earth.
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The components of vector A are:
Korvikt [17]

here as it is given that x component of the vector is positive while y component of the vector is negative so we can say the vector must inclined in Fourth quadrant.

So angle must be more than 270 degree and less than 360 degree

Now in order to find the value we can say that

tan\theta = \frac{opposite\: side}{adjacent\: side}

tan\theta = \frac{8.6}{6.1}

\theta = tan^{-1}1.41

\theta = 54.65^0

so it is inclined at above angle with X axis in fourth quadrant

Now if angle is to be measured counterclockwise then its magnitude will be

\theta = 360 - 54.65 = 305.3^0

so the correct answer will be 305 degree

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3 years ago
A 2.00 kg box slides on a rough, horizontal surface, hits a spring with a speed of 1.90 m/s and compresses it a distance of 10.0
oksian1 [2.3K]

Answer:

Explanation:

Given

mass of box m=2\ kg

speed of box v=1.9\ m/s

distance moved by the box x=10\ cm

coefficient of kinetic friction \mu _k=0.66

Friction  force f_r=\mu_kN

f_r=0.66\times mg

f_r=0.66\times 2\times 9.8=12.936 \N

Kinetic Energy of box will be utilize to overcome friction and rest is stored in spring in the form of elastic potential energy

\frac{1}{2}mv^2=f_r\cdot x+\frac{1}{2}kx^2

\frac{1}{2}\times 2\times 1.9^2=12.936\times 0.1+\frac{1}{2}\times k\times (0.1)^2

3.61-1.2936=0.005\times k

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3 0
3 years ago
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Which is a substance that takes the shape and volume of its container?

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Two balls are thrown against a wall. Ball 1 has a much higher speed than ball 2.
Sunny_sXe [5.5K]

Let both the balls have the same mass equals to m.

Let v_1 and v_2 be the speed of the ball1 and the ball2 respectively, such that

v_1>v_2\;\cdots(i)

Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.

The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, v, is \frac 12 m v^2

and the potential energy is due to the change in height is mgh [where g is the acceleration due to gravity]

So, the total energy of ball1,

=\frac 12 m v_1^2 + mgh\;\cdots(ii)

and the total energy of ball1,

=\frac 12 m v_2^2 + mgh\;\cdots(iii).

Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)

So, \frac 12 m v_1^2 >\frac 12 m v_2^2

Now, from equations (ii) and (iii)

The total energy of ball1 hi higher than the total energy of ball2.

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Anastaziya [24]
Supply and demand goes up .
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4 years ago
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