Answer:
W = ½ m v²
Explanation:
In this exercise we must solve it in parts, in a first part we use the conservation of the moment to find the speed after the separation
We define the system formed by the two parts of the rocket, therefore the forces during internal separation and the moment are conserved
initial instant. before separation
p₀ = m v
final attempt. after separation
= m /2 0 + m /2 v_{f}
p₀ = p_{f}
m v = m /2 
v_{f}= 2 v
this is the speed of the second part of the ship
now we can use the relation of work and energy, which establishes that the work is initial to the variation of the kinetic energy of the body
initial energy
K₀ = ½ m v²
final energy
= ½ m/2 0 + ½ m/2 v_{f}²
K_{f} = ¼ m (2v)²
K_{f} = m v²
the expression for work is
W = ΔK = K_{f} - K₀
W = m v² - ½ m v²
W = ½ m v²
C because the length & the path i took determines the distance .
Answer:
1.5 ohm, 9 ohm
Explanation:
Total resistance, R = 10.5 ohm
Let the resistance of one piece is r and then the resistance of another piece is 10.5 - r.
According to question, the resistance of one piece is equal to the 6 times the resistance of another piece.
so, 6 r = 10.5 - r
7 r = 10.5
r = 1.5 ohm
Thus, the resistance of one piece is 1.5 ohm and resistance of another piece is 10.5 - 1.5 = 9 ohm.
Answer:
Gases
Explanation:
Gas has particles that are all very far apart and are moving quickly causing them to have very little to no attraction.