Study the four transverse waves shown. Compare the properties of waves B, C, & D to that of wave A.

Students launch a steel ball horizontally from a tabletop. The initial horizontal speed of the ball is v, the tabletop height ab

Nadya [2.5K]

Answer:

5.9 m

Explanation:

v=6m/s

H=5m

h=0.17m

g=10 m/s

First we find the time in which ball reaches the entrance of coffee can. For this purpose the ball has to travel a distance S vertically downward such that

S= 5-0.17 = 4.83 m

While falling down Vi =0

g= 10 m/sec2

t = ?

S=vit+1/2 gt2

==> 4.83=0+0.5×10× $t^{2}$

==> 4.83=5× $t^{2}$

==> $t^{2}$ =4.83/5 = 0.97

==> t= 0.98 sec

So in this time the ball reaches the coffee can height level. Now let's calculate horizontal distance covered by the ball in this time.

Horizontal distance = horizantal velocity × time

= 6 × 0.98 = 5.9 m

6 0

3 years ago

Helppp plss

shutvik [7]

Answer:

a) P = 149140[w]; b) 1491400[J]; c) v = 63.06[m/s]

Explanation:

As the solution to the problem indicates, we must convert the power unit from horsepower to kilowatts.

P = 200 [hp]

$200[hp] * 745.7 [\frac{watt}{1 hp}]\\149140[watt]$

Now the power definition is known as the amount of work done in a given time

P = w / t

where:

w = work [J]

t = time [s]

We have the time, and the power therefore we can calculate the work done.

w = P * t

w = 149140 * 10 = 1491400 [J]

And finally, we can calculate the velocity using, the expression for kinetic energy

$E_{k}=w=0.5*m*v^{2}\\ where:\\v = velocity[m/s]\\m=mass=750[kg]\\w=work=1491400[J]\\$

The key to solving this problem is to recognize that work equals kinetic energy

$v=\sqrt{\frac{w}{0.5*m}} \\v=\sqrt{\frac{1491400}{0.5*750}} \\v=63.06[m/s]$

3 0

3 years ago

Light incident on a surface at an angle of 45 degrees undergoes diffused reflection. At what angle will it reflect?

Alexus [3.1K]

at any angle between -90 and 90 degrees. In the diffused reflection ,the surface is rough and the direction of light in not the same as the incident light. It can be reflected at any angle

4 0

3 years ago

Read 2 more answers

Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and

mart [117]

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

$\lambda=\frac{v}{f}$

where

v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

$f=288 Hz$

$v=1.45\cdot 10^3 m/s$

Substituting into the equation, we find the wavelength:

$\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m$

3 0

4 years ago

A series-parallel circuit consists of two parallel circuits connected in series across a 45-V source. One parallel branch consis

musickatia [10]

Answer:

The answer to the question is

The current through R4 = 0.5865 mA

Explanation:

To solve this we list out the known thus

Voltage source = 45-V

Firsrt parallel circiuit has resistances of R1 = 17 kΩ and R2 = 23 kΩ

Second parallel circiuit has resistances of R3 = 45 kΩ and R4 = 55 kΩ

we first find the current flowing in the circuit by finding thr sum of the total resistance in eah parallel circuit

Firsrt parallel circiuit, for circuit in parallel, sum of resistance 1/RT1 = 1/ R1 + 1/R2 = 1/17+1/23 = 0.1023017 therefore RT1 = 1/0.1023017 = 9.775 kΩ

Similarly we have for the second parallel circuit 1/RT2 = 1/R3 + 1/R4

= 1/45 + 1/55 = 0.0404 Hence RT2 = 1/0.0404 = 24.75 kΩ

This means that the 9.775 kΩ and the 24.75 kΩ are in series hence total resistance of the circuit = sum of all resistances in series

= 9.775 kΩ + 24.75 kΩ = 34.525 kΩ

However current, I is given by V/R = 45-V/34.525 kΩ = 1.303 × 10⁻³ A or 1.303 mA

From the current divider rule, I4 = I × (R4/(R3+R4)

That is the currrent flowing throuhgh R4 = 1.303 × (45/(45+55)) = 0.5865 mA

3 0

4 years ago