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diamong [38]
4 years ago
9

En una fundición hay un horno eléctrico con capacidad para fundir totalmente 540 kg de cobre. Si la temperatura inicial del cobr

e es de 20º C ¿Cuántos kJ de energía calorífica en total se necesitan para fundir el cobre?
Physics
1 answer:
11Alexandr11 [23.1K]4 years ago
3 0

Answer:

Q = 2.95*10^5 kJ

Explanation:

In order to calculate the energy required to melt the cooper, you first calculate the energy required to reach the boiling temperature. You use the following formula:

Q_1=mc(T_b-T_1)     (1)

m: mass of cooper = 540 kg

c: specific heat of cooper = 390 J/kg°C

Tb: boiling temperature of cooper = 1080°C

T1: initial temperature of cooper = 20°C

You replace the values of the parameters in the equation (1):

Q_1=(540kg)(390\frac{J}{kg.\°C})(1080\°C-20\°C)=2.23*10^8J

Next, you calculate the energy required to melt the cooper by using the following formula:

Q_2=mL_f         (2)

Lf: melting constant of cooper = 134000J/kg

Q_2=(540kg)(134000\frac{J}{kg})=7.24*10^7J

Finally, the total amount of energy required to melt the cooper from a temperature of 20°C is the sum of Q1 and Q2:

Q=Q_1+Q_2=2.23*10^8J+7.24*10^7J=2.95*10^8J=2.95*10^5kJ

The total energy required is 2.95*10^5 kJ

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3 years ago
A heavy rope, 50 ft long, weighs 0.5 lb/ft and hangs over the edge of a building 120 ft high.
Thepotemich [5.8K]

Answer:

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(b) 468.75 ft lb

Explanation:

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(a)

Force=wl/2 where w is uniformly distributed load of 0.5 lb/ft and l is the length of the rope

Force=0.5*50/2=12.5

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(b)

Assuming that the weight of the rope is concentrated in two places, half is 12.5 feet down and the other half is 37.5 feet down. The center of mass of the top half is 12.5 feet down. The weight of the top half is 12.5

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3 years ago
A pendulum is moving 2.0 m/s at the bottom of its swing. How high vertically will it go before it begins to swing back? Group of
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Answer:

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Given that,

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