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horsena [70]
3 years ago
5

The ideas that the universe began at a single point and has been expanding since its formation are the main premises of which of

the following?
A. The big bang theory

B. Nucleosynthesis

C. Redshifting

D. The big crunch theory
Physics
1 answer:
Basile [38]3 years ago
6 0
The big bang theory describes and claims that the universe has been created through cosmic expansion originating from a single point.

Where it was explained that the nature of now objects in space being in constant space was due to once a high density and high density point produce a scattering or explosion of the cosmic energy . Other theories have also supported this theory originally and first documented by Georges Henri Joseph Édouard Lemaître an astronomer and physicist.
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The following time dependent force is applied to a 2 kg block that is initially at rest on a frictionless and horizontal surface
DerKrebs [107]

Answer:

The displacement of the block is 9 m.

Explanation:

Given that,

Mass of block = 2 kg

Time = 3 sec

The force is

F(t)=4t

The acceleration is

a=\dfrac{F}{m}

Put the value into the formula

a=\dfrac{4t}{2}

a=2t

We need to calculate the velocity

Using formula of acceleration

v=\int_{0}^{t}{a dt}

Put the value into the formula

v=\int_{0}^{3}(2t dt)

v=(\dfrac{2t^2}{2})_{0}^{3}

v=(t^2)_{0}^{3}

v=9\ m/s

We need to calculate the displacement

Using formula of velocity

s=\int_{0}^{3}(v dt)

s=(t^2)_{0}^{3}

s=(\dfrac{t^3}{3})_{0}^{3}

s=9\ m/s

Hence, The displacement of the block is 9 m.

8 0
3 years ago
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A windmill is example of a <br>a.generator <br>b.resistor <br>c.insulator<br>d.motor
Alexandra [31]
The answer is a. generator!
4 0
3 years ago
1. Order the materials from smallest refractive index to largest refractive index.
slavikrds [6]

Air = 1

Water = 1.33

Glass = 1.52

Quartz = 1.46

Diamond = 2.42

3 0
3 years ago
a block of wood is found to have dimensions of 6.21 cm x 4.63 cm x 5.34 cm. Calculate the volume of the block
34kurt

Answer:

153.54 cm³

Explanation:

The formula for the volume of a cube is v = lwh, where l is the length, w is the width, and h is the height of the block.  Multiply, 6.21*4.63*5.34 = 153.54

7 0
3 years ago
An ideal gas initially at 4.00atm and 350 K is permitted
Nuetrik [128]

Explanation:

It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is P_{2} and final temperature is T_{2}.

(a)   We know that for a monoatomic gas, value of \gamma is \frac{5}{3}[/tex].

And, in case of adiabatic process,

                PV^{\gamma} = constant              

also,         PV = nRT

So, here    T_{1} = 350 K,    V_{1} = V,  and   V_{2} = 1.5 V

Hence,      \frac{T_{2}}{T_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma -1}

         \frac{T_{2}}{350 K} = (\frac{V}{1.5V})^{\frac{5}{3} -1}

          T_{2} = 267 K

Also,   P_{1} = 4.0 atm,   V_{1} = V,  and   V_{2} = 1.5 V

        \frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma}

        \frac{P_{2}}{4.0 atm} = (\frac{V}{1.5V})^{\frac{5}{3}}

            P_{2} = 2.04 atm

Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.

(b) For diatomic gas, value of \gamma is \frac{7}{5}[/tex].

As,        PV^{\gamma} = constant              

also,         PV = nRT

T_{1} = 350 K,    V_{1} = V,  and   V_{2} = 1.5 V

              \frac{T_{2}}{T_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma -1}

         \frac{T_{2}}{350 K} = (\frac{V}{1.5V})^{\frac{7}{5} -1}

          T_{2} = 289 K

And,   P_{1} = 4.0 atm,   V_{1} = V,  and   V_{2} = 1.5 V

                \frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{\gamma}

        \frac{P_{2}}{4.0 atm} = (\frac{V}{1.5V})^{\frac{7}{5}}

            P_{2} = 2.27 atm

Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.

6 0
4 years ago
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