How many moles are equal to 2.188E+23 atoms of iron?

1 answer:

7 0

2.188*10^23 atoms of iron
6.022*10^23 atoms/mole
(2.188*10^23 atoms of iron)/(6.022*10^23 atoms/mol)~.3633 moles of iron

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The numerator is the blank number in a fraction, while the denominator is the blank number in a fraction

tigry1 [53]

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3 years ago

. How many grams of Na2SO4 are required to make 2700 mL of a 2.0 M solution?

ratelena [41]

Answer:

Explanation:

From the net ionic equation

Ba2+(aq) + SO42-(aq) ==> BaSO4(s) we see that 1 mole Ba2+ reacts with 1 mole SO42- to -> 1 mol BaSO4

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6 0

2 years ago

Read 2 more answers

Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find

FromTheMoon [43]

Answer: The concentration of $SO_4^{2-}$ at equilibrium is 0.00608 M

Explanation:

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

$H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)$