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Rasek [7]
3 years ago
11

This graph shows the displacements and times for the winner of a horse race. What was the average speed of the horse that won th

e race? 0.05 m/s 20 m/s 45 m/s 285 m/s Coordinate graph titled Displacement versus Time for the Winner of a Horse Race showing Time in seconds on horizontal axis ranging from zero to twenty five and Distance in meters on vertical axis ranging from zero to three hundred. The graph shows a line rising from zero to three hundred after fifteen seconds.

Physics
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

The answer is 20m/s

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The two factors that affect the period of a pendulum are the length of the string and the distance in which the pendulum falls.

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What happens when you drop a sugar cube into a mug of hot tea
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The sugar cube disolves
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A ball rolls down the hill which has a vertical height of 15 m. Ignoring friction what would be the gravitational potential ener
trasher [3.6K]

a) Potential energy: 147 m [J]

The gravitational potential energy of an object is given by

U=mgh

where

m is its mass

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object above the ground

In this problem,

h = 15 m

We call 'm' the mass of the ball, since we don't know it

So, the potential energy of the ball at the top of the hill is

U=(m)(9.8)(15)=147 m (J)

b) Velocity of the ball at the bottom of the hill: 17.1 m/s

According to the law of conservation of energy, in absence of friction all the potential energy of the ball is converted into kinetic energy as the ball reaches the bottom of the hill. Therefore we can write:

U=K=\frac{1}{2}mv^2

where

v is the final velocity of the ball

We know from part a) that

U = 147 m

Substituting into the equation above,

147 m = \frac{1}{2}mv^2

And re-arranging for v, we find the velocity:

v=\sqrt{2\cdot 147}=17.1 m/s

5 0
3 years ago
Bob, of mass m, drops from a tree limb at the same time that Esther, also of mass m, begins her descent down a frictionless slid
galben [10]

Answer:

Explanation:

They have the same kinetic energy

5 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10 m. Make a rough estimate of the pressure at which the finite volume
timurjin [86]

Answer:

P = 1 x 10⁸ Pa

Explanation:

given,

radius = 2.0 ×10⁻¹⁰ m

Temperature

T = 300 K

Volume of gas molecule =

V = \dfrac{4}{3}\pi r^3

V = \dfrac{4}{3}\pi (2\times 10^{-10})^3

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we know,

P  V = 1 . k T

k = 1.38  x 10⁻²³ J/K

P(33.51 x 10⁻³⁰) = 1 . (1.38  x 10⁻²³) x 300

P = 1.235 x 10⁸ Pa

for 1 significant figure

P = 1 x 10⁸ Pa

6 0
3 years ago
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