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cluponka [151]
3 years ago
11

A 1.638 Gram pure sample of a compound containing only carbon hydrogen and oxygen was burned in excess oxygen gas 3.117 g of car

bon dioxide and 1.911 g of water were produced find the empirical formula of the compound
Chemistry
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

C2H6O

Explanation:

<u>First, find the masses of C, H, and O. I used ratios.</u>

3.117g CO2  x  1 mol CO2/44.01g CO2  x  1 mol C/1 mol CO2  x  12.01g C/1 mol C = 0.850606 g C

1.911g H2O  x  1 mol H2O/18.016g H2O  x  2 mol H2O/1 mol H2O  x  1.008g H/1 mol H = 0.213842 g H

To find the mass of oxygen, just add the masses of C and H together and subtract that from the total mass of the sample.

1.638 - (0.850606 + 0.213842) = 0.57355 g O

<u>Second, find the moles of C, H, and O.</u>

0.850606g C  x  1 mol C/12.01g C = 0.070825 mol C

0.213842g H  x  1 mol H/1.008g H = 0.212145 mol H

0.57355 g O  x  1 mol O/16g O = 0.035847 mol O

<u>Finally, divide the number of moles of each element by the smallest value of moles calculated. In this case, the smallest value is 0.035847.</u>

0.070825/0.035847 = 2

0.212145/0.035847 = 6

0.035847/0.035847 = 1

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