Answer:
147.456077993 Hz
Explanation:
= Frequency of the sonar = 22 kHz
= Velocity of the whale = 4.95 m/s
v = Speed of sound in water = 1482 m/s
The difference in frequency is given by
The difference in frequency is 147.456077993 Hz
Answer: The option (C) is correct. The energy travels horizontally.
Explanation: When the pebble is thrown into a calm lake, there will be disturbance in the lake. The ripples are formed from the center and move outward because the energy is carried out from particle to particle.
The distribution of the energy among the particles starts from center and it will carry out outward. This disturbance will occur horizontally.
Therefore, the energy travels horizontally.
Answer:
rock of mass m is dropped to the ground from a height h. A second rock, with mass 2m, is dropped from the same height. When the second rock strikes the ground, what is its kinetic energy? (a) Twice that of the first rock, (b) four times that of the first rock, (c) same as that of the first rock, (d) half as much as that of the first rock, (e) impossible to determine.
Answer:
The target was higher than the cannon
Explanation:
Given that a cannon ball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s.
The initial velocity must be 56 m/s, while the final velocity will be 35 m/s.
When an object is thrown upward with an initial velocity, the object continues to move upwards with decreasing in magnitude of velocity till it reaches the maximum height where the final velocity will be equal to zero.
In this question, since the final velocity is less than the initial velocity, we can conclude that the target is higher.
Therefore, the target was higher than the cannon.
Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the amplitude of the wave
Using formula of velocity
Put the value into the formula
Hence, The amplitude of the wave is 0.02 m.
