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Sergeeva-Olga [200]
3 years ago
10

Al2(SO4)3 + Ca(OH)2 → Al(OH)3 + CaSO4

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Hey there!

I assume you want this equation balanced.

Al₂(SO₄)₃ + Ca(OH)₂ → Al(OH)₃ + CaSO₄

Let's start by balancing the polyatomic ions, starting with SO₄.

There are 3 on the left and 1 on the right, so let's add a coefficient of 3 in front of the CaSO₄.

Al₂(SO₄)₃ + Ca(OH)₂ → Al(OH)₃ + 3CaSO₄

Now let's balance the polyatomic ion OH.

There are 2 on the left and 3 on the right, so let's put a coefficient of 3 in front of Ca(OH)₂ and a coefficient of 2 in front of Al(OH)₃.

Al₂(SO₄)₃ + 3Ca(OH)₂ → 2Al(OH)₃ + 3CaSO₄

Now let's balance Al.

There are 2 on the left and 2 on the right, so Al is already balanced.

Lastly, let's balance Ca.

There are 3 on the left and 3 on the right, so Ca is already balanced.

This means we're done! Here's the final balanced equation:

Al₂(SO₄)₃ + 3Ca(OH)₂ → 2Al(OH)₃ + 3CaSO₄  

Hope this helps!

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When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water
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Answer:

Mass = 48 g

Explanation:

Given data:

Number of moles of H₂ react= 3.00 mol

Number of moles of O₂ react= 1.50 mol

Number of moles of water formed = 3.00 mol

Mass of oxygen react = ?

Solution:

Chemical equation:

2H₂ + O₂    →      2H₂O

It is stated in given question when 1.50 moles of oxygen react 3.00 moles of water are formed. Thus, mass of 1.50 moles of oxygen is

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 1.50 mol × 32 g/mol

Mass = 48 g

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