Parents SHOULDN'T avoid sharing their own mistakes with children.
To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:
Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr]
HOBr = 0.50 M
KOBr = 0.30 M = OBr-
<span> HOBr + H2O <-> H+ + OBr- </span>
<span>I 0.50 - 0 0.30 </span>
<span>C -x x x
</span>---------------------------------------------
<span>E(0.50-x) x (0.30+x) </span>
<span>Assuming that the value of x is small as compared to 0.30 and 0.50 </span>
<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>
<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
Answer:
a) First-order.
b) 0.013 min⁻¹
c) 53.3 min.
d) 0.0142M
Explanation:
Hello,
In this case, on the attached document, we can notice the corresponding plot for each possible order of reaction. Thus, we should remember that in zeroth-order we plot the concentration of the reactant (SO2Cl2 ) versus the time, in first-order the natural logarithm of the concentration of the reactant (SO2Cl2 ) versus the time and in second-order reactions the inverse of the concentration of the reactant (SO2Cl2 ) versus the time.
a) In such a way, we realize the best fit is exhibited by the first-order model which shows a straight line (R=1) which has a slope of -0.0013 and an intercept of -2.3025 (natural logarithm of 0.1 which corresponds to the initial concentration). Therefore, the reaction has a first-order kinetics.
b) Since the slope is -0.0013 (take two random values), the rate constant is 0.013 min⁻¹:
c) Half life for first-order kinetics is computed by:
d) Here, we compute the concentration via the integrated rate law once 1500 minutes have passed:
Best regards.
I believe it’s Refractive index
Complete Question:
A certain ionic compound X has a solubility in water of .765g/ml at 5 degrees C. Calculate the mass of X that's dissolved in 3 L of a saturated solution of X in the water at this temp. Be sure your answer has the correct unit symbol and significant digits.
Answer:
2.29 kg
Explanation:
A saturated solution is a solution that has the maximum amount of solute diluted at it, so if more solute is added, it will precipitate. The solutions can also be unsaturated (when more solute can be dissolved) or supersaturated (when there is more solute dissolved than the maximum. It's a very unstable solution).
The saturation is measured by the solubility, which indicates how much mass of the solute can be added to a certain volume of the solvent. So, the solubility (S) is the mass (m) divided by the volume (V).
For a solution with 3 L = 3000 mL,
S = m/V
0.765 = m/3000
m = 3000 * 0.765
m = 2295 g
m = 2.29 kg
