HBr molar mass is 80.9 g/mol
this means in 80.9 g - 1 mol of HBr
1 mol consists of 6.022 x 10²³ molecules of HBr
that means in 80.9 g HBr there are 6.022 x 10²³ molecules of HBr
therefore in 42.5 g of HBr there are 6.022 x 10²³/80.9 * 42.5
the number of HBr molecules are therefore - 3.16 x 10²³ HBr molecules
D) melting ice because u can freeze the “ice” back into that state of matter this is called a physical change. HOPE THIS HELPED
Answer:
SO2(g) + O2(g) SO3(g) (needs to be balanced. Balance it by placing a 1/2 in front of the 02.) This is a 5-sig-fig problem, so when you calculate your molar masses, you must use all of the sig figs available to you from the periodic table. That's how you can get this problem correct. Melissa Maribel likes to round the numbers from the periodic table, and usually that is ok. But for problems where you have many sig figs, your molar masses from the periodic table must have at least as many sig figs as your data. Therefore, for each oxygen atom, please use 15.9994 g/mol. For each sulfur atom, please use 32.066 g/mol. Thank you.
Answer:
specific weight = 49.7 lb/ft^3
specific gravity = 0.797
Explanation:
From Appendix A,
pk = 1.58 slug/ft^3
pea = 1.53 slug/ft^3
volume of kerosene is
Vk = 14 ft^3 - 10 ft^3 = 4 ft^3
The total weight of the mixture is therefore
W = pk g Vk + pea g Vea
= (1.58 slug/ft3) (32.2 ft/s^2) (4 ft^3) + (1.53 slug/ft^3) (32.2 ft/s^2) (10 ft^3)
= 696.16 lb
The specific weight and specific gravity of the mixture are
γm = W
/V
γm = 696.16 lb/ 14 ft^3 = 49.73 lb/ ft^3 = 49.7 lb/ft^3
Sm = γm / γv
Sm = 49.73 lb/ft^3/ 62.4 lb/ft^3 = 0.797