Question

What is the theoretical yield if 45.6 g of benzene react?

Answer 1

Answer:

65.7g of chlorobenzene is expected to be produced.

Explanation:

The reaction equation is:

$C_{6} H_{6} (l) + Cl_{2} (g)$ → $C_{6} H_{5}Cl (s) + HCl(g)$

Mole ratio of C6H6 to CH5Cl is 1 : 1: that is for every 1 mole of benzene used in the reaction, 1 molee of chlorobenzene is produced.

1 mole of C6H6 - 78.11 g

?? mole of C6H6 - 45.6 g  ⇒ $\frac{45.6}{78.11}$ = 0.58 moles used in reaction

Consequently,

1 mole of chlorobenzene - 112.56 g

0.58 moles of chlorobenzene = 112.56 × 0.58

= 65.7g