Suppose you are standing on a scale in an elevator that is accelerating upward. Will the scale read your weight as larger for sm
1 answer:
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Answer:
100 m
Explanation:
Arthur and Betty should be walking the same amount of time if they start walking at the same time and stop when they meet = t
Speed of Arthur = 3 m/s
Speed of Betty = 2 m/s
Distance = Speed × time
Distance covered by Arthur = 3t
Distance covered by Betty = 2t
The distance covered by both of them will be 100 m
The speed of dog is 5 m/s
Spot is running back and forth at 5 m/s for 20 seconds
In 20 seconds the distance covered by the dog is
Answer:
0.304 m/s2
Explanation:
If the first child is pushing with a force of 69N to the right and the 2nd child is pushing with a force of 91N to the left. Then the net pushing force is 91 - 69 = 22 N to the left. Subtracted by 15N friction force then the system of interest is subjected to F = 7 N net force tot he left.
We can use Newton's 2nd law to calculate the net acceleration of the system