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Answer:
63.6%
Explanation:
The given compound is:
N₂O;
The problem here is to find the percent composition of nitrogen in the compound.
First find the molar mass of the compound:
Molar mass of N₂O = 2(14) + 16 = 44g/mol
So;
Percentage composition of Nitrogen = 
x 100 = 63.6%
The rate of a reaction would be one-fourth.
<h3>Further explanation</h3>
Given
Rate law-r₁ = k [NO]²[H2]
Required
The rate of a reaction
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
Can be formulated:
Reaction: aA ---> bB
or
The concentration of NO were halved, so the rate :
![\tt r_2=k[\dfrac{1}{2}No]^2[H_2]\\\\r_2=\dfrac{1}{4}k.[No]^2[H_2]\\\\r_2=\dfrac{1}{4}r_1](https://tex.z-dn.net/?f=%5Ctt%20r_2%3Dk%5B%5Cdfrac%7B1%7D%7B2%7DNo%5D%5E2%5BH_2%5D%5C%5C%5C%5Cr_2%3D%5Cdfrac%7B1%7D%7B4%7Dk.%5BNo%5D%5E2%5BH_2%5D%5C%5C%5C%5Cr_2%3D%5Cdfrac%7B1%7D%7B4%7Dr_1)
Answer: All options (I, II, III, IV, V)
Explanation: The answer is all options because they never reach equilibrium or intersect at a region as the both decrease at the same rate.
Answer:
What will happen to Uk if you double the mass?
Explanation:
Uk = 0.5 * m * v²
You see that both m and v are variable, which means that both m and v can be any number. Regardless of the numbers you put in for m or v, the formula to calculate the kinetic energy (Uk) remains valid.
You could ask
1. What will happen to Uk if you double the mass?
2. What will happen to Uk if you double the velocity?
please see and understand(!) that the relationship between Uk an v² is indeed the velocity squared....
EXTRA
Uk = 0.5 * m * (v)²
Suppose the m = 3kg and velocity = 5 m/s
What is the Uk?
Well if you know the formula you can use your calculator to find out:
Uk = 0.5 * m * (v)²
Uk = 0.5 * 3 * (5)²
Uk = 0.5 * 3 * 25
Uk = 37.5 kgm/s²
Again you ask what will happen to Uk if you double the velocity?
At first it was 5 m/s and now it doubles, which means it now has that value *2
The new velocity is 5 *2 = 10 m/s
Uk = 0.5 * m * (v)²
Uk = 0.5 * 3 * (10)²
Uk = 0.5 * 3 * 100
Uk = 150 kgm/s²
150 = 4 * 37.5
So now you see that if you double your velocity, the Uk will be 2² = 4 times as big !
