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2 years ago

WHICH OF THE FOLLOWING WILL RESULT FROM INCREASING THE TEMPERATURE OF A GAS - APEX

Chemistry

2 answers:

BaLLatris [955]2 years ago

8 0

Answer: the pressure of a gas will increase -Apex

Explanation:

Juli2301 [7.4K]2 years ago

6 0

Answer:

it will stay a gas

Explanation:

by heating up a gas you are making sure the gas stays a gas

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A substance made of two or more elements chemically combined in a set ratio, or proportion, is called a ___.

snow_lady [41]

Hey there!

The correct answer to your question is a compound.

A substance of two or more elements chemically combined in a set ratio, or proportion, is called a compound.
This is because compounds are made of two or more elements. Table salt is an example of a compound because it is made up of the elements chlorine and sodium.

Hope this helps you.
Have a great day!

7 0

2 years ago

What is the effect of molecular weight on melting and boiling point of alkanes??

Readme [11.4K]

Answer:

Their melting and boiling points of alkanes are relatively low. The higher the molecular weight (the greater the number of carbons), the higher the boiling point.

8 0

3 years ago

If PbI2(s) is dissolved in 1.0MNaI(aq) , is the maximum possible concentration of Pb2+(aq) in the solution greater than, less th

fredd [130]

Answer:

$\mathbf{s =\sqrt [3]{\dfrac{K_{sp}}{4}}}$

Less than the concentration of Pb2+(aq) in the solution in part ( a )

Explanation:

From the question:

We assume that s to be the solubility of PbI₂.

The equation of the reaction is given as :

PbI₂(s) ⇌ Pb²⁺(aq) + 2I⁻(aq); Ksp = 7 × 10⁻⁹

[Pb²⁺] = s

Then [I⁻] = 2s

$K_{sp} =\text{[Pb$^{2+}$][I$^{-}$]}^{2} = s\times (2s)^{2} = 4s^{3}\\s^{3} = \dfrac{K_{sp}}{4}\\\\s =\mathbf{ \sqrt [3]{\dfrac{K_{sp}}{4}}}\\\\\text{The mathematical expressionthat can be used to determine the value of }\mathbf{s =\sqrt [3]{\dfrac{K_{sp}}{4}}}$

The Concentration of Pb²⁺ in water is calculated as :

$\mathbf{s =\sqrt [3]{\dfrac{K_{sp}}{4}}}$

$\mathbf{s =\sqrt [3]{\dfrac{7*10^{-9}}{4}}}$

$\mathbf{s} =\sqrt[3]{1.75*10^{-9}}$

$\mathbf{s} =\mathbf{1.21*10^{-3} \ mol/L }$

The Concentration of Pb²⁺ in 1.0 mol·L⁻¹ NaI

$\mathbf{PbCl{_2}} \leftrightharpoons \ \ \ \ \ \ \ \mathbf{Pb^{2+}} \ \ \ \ \ + \ \ \ \ \ \ \ \mathbf{2 I^-}$

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mathbf0} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{1.0}$

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{+x} \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{+2x}$

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{+x} \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{1.0+2x}$

The equilibrium constant:

$K_{sp} =[Pb^{2+}}][I^-]^2 \\ \\ K_{sp} = s*(1.0*2s)^2 =7*1.0^{-9} \\ \\ s = 7*10^{-9} \ \ m/L$

It is now clear that maximum possible concentration of Pb²⁺ in the solution is less than that in the solution in part (A). This happens due to the common ion effect. The added iodide ion forces the position of equilibrium to shift to the left, reducing the concentration of Pb²⁺.

3 0

3 years ago

The distance between particles______when the temperature increases and

LekaFEV [45]

Answer:

increases

decreases

Explanation:

The distance between particles increases when the temperature increases and decreases when temperature decreases.

Temperature changes in a system causes the particle of such system to behave in different ways.
When particles gain heat energy as their temperature increases, they begin to move further apart.
As their temperature reduces they tend to coalesce.

5 0

2 years ago

This chart shows the global temperature anomaly (the difference of the expected temperature and the actual temperature) over a s

polet [3.4K]

I think its 1 3 and 4

8 0

3 years ago

Read 2 more answers