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postnew [5]
3 years ago
5

You are out running and the first mile takes you 10 minutes. The second mile takes 20 minutes. This is an example of ?

Physics
2 answers:
AlladinOne [14]3 years ago
7 0
This is an example of negative acceleration. It's also an example of simultaneous cardiovascular and muscle fatigue.
Jet001 [13]3 years ago
3 0

Answer:

Negative acceleration.

Explanation:

It is given that, you are out running and the first mile takes you 10 minutes. The second mile takes 20 minutes. Here, to cover same distance time increases. It is the case of negative acceleration or deceleration.

Similarly, if the distance travelled is same also the time taken to cover this distance is decreasing is called positive acceleration.

So, the above case is an example of negative acceleration. Hence, this is the required solution.

You might be interested in
A space station consists of three modules, connected to form an equilateral triangle of side length 82.0 m. Suppose 100 people,
CaHeK987 [17]

Answer:

Angular momentum of the system is 16221465.4617 kgm²/s

Explanation:

Given that;

length of the side of the triangle L =  82 M

m = 75.0 kg × 100 = 7500 kg

distance of each vertex from center R = L/√3 = 82/√3 = 47.34 m

effective acceleration a = 9.8 / 2 = 4.9 m/s²

we know that; effective acceleration is being provided by centripetal acceleration.

so

a = R × w²

rate of rotation w = √( a / R) = √( 4.9 / 47.34)  = 0.3217 rad/seconds

Moment of Inertia I = 3mR²

we substitute

I = 3 × 7500 × (47.34)²

Also, Angular momentum L is expressed as;

L = I × w

so

L = 3 × 7500 × (47.34)² × 0.3217

L =  16221465.4617 kgm²/s

Therefore, Angular momentum of the system is 16221465.4617 kgm²/s

8 0
3 years ago
A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is
maksim [4K]
D = v^2 / 2ug

d=  3.5^2 / 0,15 x 9.8 m/s^2

the answer should be around 4.2m

hope this helps
8 0
3 years ago
Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reacti
NeTakaya

Answer : The mass of NaN_3 required is 71.175 grams.

Explanation :

To calculate the moles of nitrogen gas, we use the equation given by ideal gas :

PV = nRT

where,

P = Pressure of nitrogen gas = 763 torr

V = Volume of the nitrogen gas = 40.0 L

n = number of moles of gas = ?

R = Gas constant = 62.364\text{ L.torr }mol^{-1}K^{-1}

T = Temperature of helium gas = 25^oC=273+25=298K

Putting values in above equation, we get:

763torr\times 40.0L=n\times 62.364\text{ L.torr }mol^{-1}K^{-1}\times 298K\\\\n=1.642mol

Now we have to calculate the moles of NaN_3.

The balanced chemical reaction is:

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced chemical reaction, we conclude that

As, 3 moles of N_2 produced from 2 moles NaN_3

So, 1.642 moles of N_2 produced from \frac{2}{3}\times 1.642=1.095 moles NaN_3

Now we have to calculate the mass of NaN_3.

Molar mass of NaN_3 = 65 g/mol

\text{Mass of }NaN_3=\text{Moles of }NaN_3\times \text{Molar mass of }NaN_3

\text{Mass of }NaN_3=1.095mole\times 65g/mole=71.175g

Therefore, the mass of NaN_3 required is 71.175 grams.

5 0
3 years ago
60 POINTS ANSWER CORRECTLY
ohaa [14]

Answer:

C ) 1.53

Explanation:

The critical angle of a material is given by the formula

sin c = \frac{1}{n}

where

c is the critical angle

n is the refractive index

This formula is valid if the second medium is air (which is the case of the problem).

In this problem, we know the critical angle:

c=40.8^{\circ}

Therefore we can rearrange the equation to find the refractive index:

n=\frac{1}{sin c}=\frac{1}{sin 40.8^{\circ}}=1.53

5 0
4 years ago
Read 2 more answers
A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the
Ilya [14]

Answer:

d) is the same as when it started from rest

Explanation:

using equation of motion

v = u + at

second law of momentum defines

F = ma

a = F /m

the equation becomes

v = u + (F/m)t

from hear

since v is directly proportional to the force and the force remain the same, the increase in the cart speed will also remain the same.

5 0
4 years ago
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