Answer:
The molar mass in g/mol is 121.4 g/m
Explanation:
Let's apply the Ideal Gases Law to solve this:
P . V = n . R. T
V = 125 mL → 0.125L
P = 754 Torr
760 Torr ___ 1 atm
754 Torr ____ (754 / 760) = 0.992 atm
Moles = Mass / Molar mass
0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K
(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)
4.07x10⁻³ mol = 0.495 g / MM
MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m
Answer:
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Answer: There are
molecules present in 183.2 grams of
gas.
Explanation:
Given: Mass = 183.2 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of water is 18 g/mol. Therefore, moles of
are calculated as follows.

According to the mole concept, there are
molecules present in one mole of a substance.
Hence, molecules present in 10.17 moles are calculated as follows.

Thus, we can conclude that there are
molecules present in 183.2 grams of
gas.