Question

The components of vector A are Ax = +2.2 and Ay = -6.9 , and the components of vector B are given are Bx =

Answer 1

For simplicity, let's call vector B-A  vector C  Then C is 
Cx = (-6.1 - 2.2)  
Cy = (-2.2 - (-6.9))  Or,
Cx = -8.3  Cy = 4.7
The magnitude is found with the Pythagorean theorem
||C|| = √(-8.3² + 4.7²) = 9.538

Answer 2

Answer:

$|\vec B - \vec A| = 9.54$

Explanation:

As we know that

$A_x = 2.2 \: A_y = -6.9$

so we have

$\vec A = 2.2 \hat i - 6.9 \hat j$

Also we know that

$B_x = -6.1 \: B_y = -2.2$

so we will have

$\vec B = -6.1 \hat i - 2.2 \hat j$

now we need to find magnitude of B - A

so we have

$\vec B - \vec A = (-6.1 \hat i - 2.2 \hat i) + (-2.2\hat j + 6.9 \hat j)$

$\vec B - \vec A = -8.3 \hat i + 4.7 \hat j$

magnitude of this vector is given as

$|\vec B - \vec A| = \sqrt{8.3^2 + 4.7^2}$

$|\vec B - \vec A| = 9.54$