Answer:
Go in notifications, it'll show if it was answered. If it doesn't show that a person answered it, wait a while, someone might respond :)
Explanation:
On the Top right of your screen, theres a bell button. Click that and it will show all the notifications. it will also show if a person answered it.
It will pop up like
*random username* answered your question! ]
Hope this helped
The total momentum of the players after collision is 130 kgm/s.
The given parameters:
- <em>Initial momentum of the returner, </em>
<em> = 0 kgm/s</em> - <em>The initial momentum of the diving player, </em>
<em> = 130 kgm/s</em>
The total momentum of the players after collision is determined by applying the principle of conservation of linear momentum as follows;
![P_f = P_i_1 + P_i_2\\\\P_f = 0 + 130\\\\P_f = 130 \ kgm/s](https://tex.z-dn.net/?f=P_f%20%3D%20P_i_1%20%2B%20P_i_2%5C%5C%5C%5CP_f%20%3D%200%20%2B%20130%5C%5C%5C%5CP_f%20%3D%20130%20%5C%20kgm%2Fs)
Thus, the total momentum of the players after collision is 130 kgm/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
A
Explanation:
Becuse its complete number
Answer:
![\mu_k=0.27](https://tex.z-dn.net/?f=%5Cmu_k%3D0.27)
Explanation:
According to the free body diagram, in this case, we have:
![\sum F_x:-F_k=ma\\\sum F_y:N=mg](https://tex.z-dn.net/?f=%5Csum%20F_x%3A-F_k%3Dma%5C%5C%5Csum%20F_y%3AN%3Dmg)
Recall that the force of friction is given by:
![F_k=\mu_k N](https://tex.z-dn.net/?f=F_k%3D%5Cmu_k%20N)
Replacing and solving for the coefficient of kinetic friction:
![-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}](https://tex.z-dn.net/?f=-%5Cmu_kN%3Dma%5C%5C-%5Cmu_k%28mg%29%3Dma%5C%5C%5Cmu_k%3D-%5Cfrac%7Ba%7D%7Bg%7D)
We have an uniformly accelerated motion. Thus, the acceleration is defined as:
![a=\frac{v_f-v_0}{t}\\a=\frac{0-5\frac{m}{s}}{1.9s}\\a=-2.63\frac{m}{s^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv_f-v_0%7D%7Bt%7D%5C%5Ca%3D%5Cfrac%7B0-5%5Cfrac%7Bm%7D%7Bs%7D%7D%7B1.9s%7D%5C%5Ca%3D-2.63%5Cfrac%7Bm%7D%7Bs%5E2%7D)
Finally, we calculate
:
![\mu_k=-\frac{-2.63\frac{m}{s^2}}{9.8\frac{m}{s^2}}\\\mu_k=0.27](https://tex.z-dn.net/?f=%5Cmu_k%3D-%5Cfrac%7B-2.63%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D%7B9.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D%5C%5C%5Cmu_k%3D0.27)