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lapo4ka [179]
3 years ago
7

If the law of conversation of momentum is true,then how does the total momentum before a collision compare to the total momentum

after a collision?
Physics
1 answer:
Oxana [17]3 years ago
4 0
<h2>Answer:The total momentum before collision is equal to the total momentum after collision.</h2>

Explanation:

Conservation of momentum states that whenever no external force is acting on a system,the total momentum is constant.

When we consider collisions,take the system as the two bodies that are colliding.

There are no external forces acting on the system.The forces that one body exerts on other come under internal forces.

So,momentum can be conserved in this case.

So,the total momentum before collision is equal to the total momentum after collision.

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Determine the amount of work done by the applied force when a 87 N force is applied to move a 15 kg object a horizontal
elena-s [515]

Answer:

391.5 J

Explanation:

The amount of work done can be calculated using the formula:

  • W = F║d
  • where the force is parallel to the displacement

Looking at the formula, we can see that the mass of the object does not affect the work done on it.

Substitute the force applied and the displacement of the object into the equation.

  • W = (87 N)(4.5 m)
  • W = 391.5 J  

The amount of work done on the object is 391.5 J in order to move it 4.5 meters with an applied force of 87 Newtons.

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2 years ago
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What does bubble universe mean
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Answer:

<h3>Our universe may live in one bubble that is sitting in a network of bubble universes in space. ... The concept is known as a "parallel universe," and is a facet of the astronomical theory of the multiverse. The idea is pervasive in comic books, video games, television and movies.</h3>
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2 years ago
Which of the following statements about energy in systems is true?
Elena-2011 [213]
Option number three is correct energy can be transformed and moved and released but it can't be destroyed and doesn't disappear.
8 0
3 years ago
How many hydrogen atoms are there in the following compound: 4CHA (2 points)
pogonyaev

Answer:

answer a, 4

Explanation:

when the 4 is before the compound it applies to the whole compound

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A block of mass 10.0 kg is pulled to the right along a rough horizontal surface with a constant horizontal force of 20.0 N. The
Yakvenalex [24]

Answer:

the magnitude of acceleration will be 1.50m/s^2

Explanation:

To calculate your acceleration, you can use your formula that states that the net force on an object is equal to the mass of the object multiplied by the acceleration of the object. Fnet=ma

if you draw out this situation and label the forces you will have your vector towards the right with a magnitude of 20.0N and then your friction vector will be pointing to the left (in other words, in the negative direction) (opposing the direction of movement) with a magnitude of 5.00N, with the 10.0 kg box in the middle.

The net force will be calculated using F1+F2=Fnet where your F1=20.0N and F2= -5.00N (since it is towards the negative direction).

you will find that Fnet=15.0N

With that, plug in the values you know to calculate the acceleration of the block:

Fnet=ma

(15.0N)=(10.0kg)a    from her you can divide both sides by 10 to isolate a:

1.50=a  (and now make sure to label the units of your answer)

a=1.50m/s^2 (which is the typical unit for acceleration)

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