Answer:
B) irreversible process
Explanation:
The process given here is irreversible.
Molar mass H₃PO₄ = 98.0 g/mol
1 mole ----- 98.0 g
? mole ------ 30.0 g
moles = 30.0 * 1 / 98.0
= 0.306 moles
hope this helps!
Answer : The amount of carbon dioxide produced is, 197.12 grams.
Explanation : Given,
Moles of ethanol = 2.24 mole
Molar mass of carbon dioxide = 44 g/mole
The balanced chemical reaction will be,
![C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O](https://tex.z-dn.net/?f=C_2H_5OH%2B3O_2%5Crightarrow%202CO_2%2B3H_2O)
First we have to calculate the moles carbon dioxide.
From the balanced chemical reaction, we conclude that
As, 1 mole of ethanol react to give 2 moles of carbon dioxide
So, 2.24 mole of ethanol react to give
moles of carbon dioxide
Now we have to calculate the mass of carbon dioxide.
![\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DCO_2%3D%5Ctext%7BMoles%20of%20%7DCO_2%5Ctimes%20%5Ctext%7BMolar%20mass%20of%20%7DCO_2)
![\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DCO_2%3D4.48mole%5Ctimes%2044g%2Fmole%3D197.12g)
Therefore, the amount of carbon dioxide produced is 197.12 grams.
Answer:
<h2>12 atm</h2>
Explanation:
To find the initial pressure we use the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
Since we are finding the initial pressure
![P_1 = \frac{P_2V_2}{V_1} \\](https://tex.z-dn.net/?f=P_1%20%3D%20%20%5Cfrac%7BP_2V_2%7D%7BV_1%7D%20%20%5C%5C)
From the question we have
![P_1 = \frac{488 \times 6}{244} = \frac{2928}{244} \\](https://tex.z-dn.net/?f=P_1%20%3D%20%20%5Cfrac%7B488%20%5Ctimes%206%7D%7B244%7D%20%20%3D%20%20%5Cfrac%7B2928%7D%7B244%7D%20%20%5C%5C%20)
We have the final answer as
<h3>12 atm</h3>
Hope this helps you