Question

A car travelling at 32 m/s decelerates at a rate of 6 m/s ^ 2 over 4 secondsWhat is the final velocity the car

Answer 1

Answer:

v=8m/s

Explanation

The initial velocity, u, of the car=32m/s

Since the car has decelerated, we negate the acceleration

This implies that,

$a=-6m{s}^{ -2}$

Time,t=4s

Let v be the final velocity,

using the relation,

$a = \frac{v - u}{t}$

We obtain the below by substitution

$- 6= \frac{v - 32}{4}$

By cross multiplying we obtain,

$- 6 \times 4 = v - 32$

$- 24=v-32$

$- 24+32=v$

v=8m/s