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Rainbow [258]
3 years ago
7

What are the three major jobs of the musculoskeletal system?

Chemistry
1 answer:
faust18 [17]3 years ago
8 0
Mechanical: they shape and support your body. Muscles attach to bones and thogether they enable body movement. Protective: bones protect internal organs e.g. the skull protects the brain and the ribcage protects the lungs and the heart
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What will happen to the volume of a gas if the Kelvin temperature of the gas is reduced to 1/4 of the original temperature and t
Temka [501]

Answer:

the volume of the gas will be 1/8 of the original value

Explanation:

7 0
3 years ago
How many atoms are bonded to the central atom in a fluorine (F2) molecule?
mylen [45]

Answer:

Only one atom are bonded to the central atom in the F_{2}.

Explanation:

Fluorine most electronegative element.

The atomic number of fluorine is 9.

Electronic configuration - 1s^{2}2s^{2}2p^{4}

Hence, it required only one electron to get noble gas[Ne] electronic configuration.

In the F_{2} molecule two fluorine atoms are bonded by single covalent bond to get stability.

Each atom share one electron and form a bond.

The structure of F_{2} molecule is as follows.

3 0
3 years ago
A mole of hydrogen atoms has 6.02 x 10^23 atoms. It occupies 22.414 L. How many hydrogen atoms are in 50.00 mL?
Greeley [361]

Answer:

This is a simple case of ratios. (1 mol)/(22.4 L)=(n mol)/(.025 L) Then we cross multiply and we get 22.4n=.025 We divide each side by 22.4 to find n=.001116 mol Then to convert the moles to atoms we multiply, and cross-cancel the units (.001116 mol)/1 xx (6.02 xx 10^23 atms)/(1 mol) and we have 6.72 xx 10^20 atoms.  I've found the trick of cross-cancelling units to be a very effective mnemonic, it always makes sure you carry out the correct calculation to find the desired units.

Explanation:

3 0
3 years ago
I WILL GIVE YOU 10 POINTS!!!
belka [17]
The answer is 268.1 u....
5 0
3 years ago
Read 2 more answers
Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
Temka [501]

The question is incomplete , complete question is:

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

(a) n = 2 to n = 4

(b) n = 2 to n = 1

(c) n = 2 to n = 5

(d) n = 4 to n = 3

Answer:

Hence the order of the transition will be : d < a < c < b

Explanation:

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6 eV

Energy of n = 2 in an hydrogen atom:

E_2=-13.6\times \frac{1^2}{2^2}eV=-3.40eV

Energy of n = 3 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy of n = 4 in an hydrogen atom:

E_4=-13.6\times \frac{1^2}{4^2}eV=-0.85 eV

Energy of n = 5 in an hydrogen atom:

E_5=-13.6\times \frac{1^2}{5^2}eV=-0.544 eV

a) n = 2 to n = 4 (absorption)

\Delta E_1= E_4-E_2=-0.85eV-(-3.40eV)=2.55 eV

b) n = 2 to n = 1 (emission)

\Delta E_2= E_1-E_2=-13.6 eV-(-3.40eV)=-10.2 eV

Negative sign indicates that emission will take place.

c) n = 2 to n = 5 (absorption)

\Delta E_3= E_5-E_2=-0.544 eV-(-3.40eV)=2.856 eV

d) n = 4 to n = 3 (emission)

\Delta E_4= E_3-E_4=-1.51 eV-(-0.85 eV)=-0.66 eV

Negative sign indicates that emission will take place.

According to Planck's equation, higher the frequency of the wave higher will be the energy:

E=h\nu

h = Planck's constant

\nu frequency of the wave

So, the increasing order of magnitude of the energy difference :

E_4

And so will be the increasing order of the frequency of the of the photon absorbed or emitted. Hence the order of the transition will be :

: d < a < c < b

7 0
4 years ago
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