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3 years ago

10

A spring is stretched 55 cm from its testing position. If the spring's constant of proportionality is 15N / m , what is the spri

ng potential energy? (Keep 3 significant figures )

2 answers:

Savatey [412]3 years ago

6 0

Answer3

:

Explanation:

dimaraw [331]3 years ago

4 0

Answer:2.27 J

Explanation:Because that’s what it was in ck12 so ion got no explanation

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If body fats has a density of 0.94 g/mL and 3.0 liters of fat are removed, how many pounds of fat were removed from the patient?

-Dominant- [34]

Answer:

6.217 pounds

Explanation:

We are given;

Density of body fats 0.94 g/mL
Volume of fats removed = 3.0 L

We are required to determine the mass of fats removed in pounds.

We need to know that;

Density = Mass ÷ volume

1 L = 1000 mL, thus, volume is 3000 mL

Rearranging the formula;

Mass = Density × Volume

= 0.94 g/mL × 3000 mL

= 2,820 g

but, 1 pound = 453.592 g

Therefore;

Mass = 2,820 g ÷ 453.592 g per pound

= 6.217 pounds

Thus, the amount of fats removed is 6.217 pounds

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3 years ago

What does the wavelength of a wave measure?

Iteru [2.4K]

Wave length measures the width of the wave

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2 years ago

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Determine how many carbon dioxide (CO2) molecules are produced if 8.45 x 1023 molecules of water (H2O) are produced 2 C2H6 (g) +

Andreas93 [3]

Ill get back to you on this

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2 years ago

Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi

bija089 [108]

<u>Answer:</u> The value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u> $B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b$

<u>Equation 2:</u> $H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}$

The net equation follows:

$B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c$

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=K_1\times K_2$

We are given:

$K_1=K_b$

$K_2=\frac{1}{K_w}$

Putting values in above equation, we get:

$K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}$

Hence, the value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

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3 years ago

How do Earth’s plates able to move?

Ann [662]

Answer:

Plates at our planet's surface move because of the intense heat in the Earth's core

Explanation:

Hopefully this helps, I believe in you! ^^

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3 years ago

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