Answer:
Electric dipole
Explanation:
the dipole axis makes an angle with the electric field. depending on direction (clockwise/aniclockwise) you get the torque
Hope this helps
Answer: Gravitational forces are action-at-a-distance forces
Explanation:
Gravitational forces are action-at-a-distance forces that act between two objects even when they are held some distance apart. For example If you watch a roller coaster car move along its course, then you are witnessing an action-at-a-distance.
Answer:
In bringing you to a halt, the sand and the water exert the same impulse on you, but the sand exerts a greater average force
Explanation:
Answer:
Explanation:
a ) A force of 6 N , causes elongation of .03 m
Spring constant
k = 6 / .03
= 200 N / m
b )
Amplitude A = .04 m .
Maximum velocity of a particle in SHM
= ωA where ω is angular velocity and A is amplitude
= x A
= x A
= 20x .04 = 0.8
Maximum velocity of a particle
= 0.8 m ² s
Minimum velocity will be zero at extreme point ( at turning point )
c )
Minimum acceleration is zero at middle point ( equilibrium position )
maximum acceleration
= ω²A
= k / m x A
= 400 x .04
= 16 m / s
d )
At halfway point velocity will be √ 3 / 2 times the maximum velocity
velocity at mid point
= √ 3 / 2 x max velocity
.866 x
= .866 x 0.8
= .693 m /s
So, If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.
<h3>Power radiated by the radiant wall heater</h3>
The power radiated by the radiant wall heater is given by P = εσAT⁴ where
- ε = emissivity = 1 (since we are not given),
- σ = Stefan-Boltzmann constant = 6 × 10⁻⁸ W/m²-K⁴,
- A = surface area of cylindrical wall heater = 2πrh where
- r = radius of wall heater = 6 mm = 6 × 10⁻³ m and
- h = length of heater = 0.6 m, and
- T = temperature of heater
Since P = εσAT⁴
P = εσ(2πrh)T⁴
Making T subject of the formula, we have
<h3>Temperature of heater</h3>
T = ⁴√[P/εσ(2πrh)]
Since P = 1.5 kW = 1.5 × 10³ W
Substituting the values of the variables into the equation, we have
T = ⁴√[P/εσ(2πrh)]
T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]
T = ⁴√[1.5 × 10³ W/(43.2π × 10⁻¹¹ W/K⁴)]
T = ⁴√[1.5 × 10³ W/135.72 × 10⁻¹¹ W/K⁴)]
T = ⁴√[0.01105 × 10¹⁴ K⁴)]
T = ⁴√[1.105 × 10¹² K⁴)]
T = 1.0253 × 10³ K
T = 1025.3 K
So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
Learn more about temperature of radiant wall heater here:
brainly.com/question/14548124