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Kryger [21]
3 years ago
6

On the moon the acceleration due to gravity is about 1/6 that on earth. If A golfer on the moon impacted the same initial veloci

ty to the ball as she does on the earth, how much further with the ball go?
Physics
1 answer:
Mamont248 [21]3 years ago
7 0

Answer: 6 times further

Explanation:

Initial velocity is the same that she uses on earth vertically and horizontally

Vertically we can say

V = -g t

If g is 1/6 earth gravity, then t is 6 times earth time.

Then, horizontally, with the same initial time, no incidence of gravity and knowing t

X= v t

Distance in the moon is 6 times distance in the earth.

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Why do raindrops fall with a constant speed during the later stages of their descents?
BartSMP [9]
Firstly they have a acceleration downwards due the force downwards due they gravitational field acting on it's mass.
as it falls it gains speed, and as it gains speed the air Resistance which is a upward force actin on the drop increases, eventually the rain drop's upward and downward forces are balanced and hence there is no RESULTANT force therefore no acceleration, so the drops falls in constant speed (terminal verlocity is a better term)

Are you wondering that why is the raindrop still moving given that the forces are balanced? If so according to Newton's 1st law an object will keep moving or Remain at rest until a RESULTANT force acts on it.
6 0
3 years ago
Bromine, a liquid at room temperature, has a boiling point
lukranit [14]

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3 0
3 years ago
Which telescope would be better viewing a faint, distant star? Why?
grin007 [14]
Reflecting telescope. Reflecting telescopes tend to have larger objective (due to the use of mirrors, mirrors are a lot cheaper than lenses) and have the ability to collect more light, while refracting telescopes are limited to objective lenses with smaller diameters due to their structural limitations (chromatic abbreviation, for example). Therefore, reflecting telescopes should be better at viewing faint distant stars
4 0
2 years ago
What is the mass of a child in a wagon that has a velocity of 10 m/s and a Momentum of 30 KG* M/S
LenKa [72]

Explanation:

sinces : Momentum = velocity × mass

then : 30 = 10 × m and m = 30 ÷ 10 = 3 kg

3 0
2 years ago
How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g
Nata [24]

Answer:

Heat of vaporization will be 22.59 j    

Explanation:

We have given mass m = 10 gram

And heat of vaporization L = 2.259 J/gram

We have to find the heat required to vaporize 10 gram mass

We know that heat of vaporization is given by Q=mL, here m is mass and L is latent heat of vaporization.

So heat of vaporization Q will be = 10×2.259 = 22.59 J

8 0
2 years ago
Read 2 more answers
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