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mixer [17]
3 years ago
11

A projectile is launched at ground level with an initial speed of 53.0 m/s at an angle of 35.0° above the horizontal. It strikes

a target above the ground 2.50 seconds later. What are the x and y distances from where the projectile was launched to where it lands?
Physics
1 answer:
Gnom [1K]3 years ago
7 0

Answer:

x = 108.5 m      y = 45.37 m,  

Explanation:

This is a projectile launching exercise, the horizontal distance it reaches is called the range and can be found by the expression

           x = v₀ₓ t

           

the initial hairiness is

          v₀ₓ = v₀ cos θ

           

           x = v₀ cos θ  t

  let's calculate

           x = 53 cos 35 2.50

           x = 108.5 m

the height of the projectile can be calculated with

            y =v₀ t - ½ g t²

             y = vo sin tea t - ½ g t²

            y = 53 sin 35 2.50 - ½ 9.8 2.5²

            y = 45.37 m

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1. Calculate the density of a 5.00 g marble which, when placed in a
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Answer:

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2. 2×10⁵ J

3. 5040 J

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1. Determination of the density.

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2. Determination of the work done.

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The work done can be obtained as follow:

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Height (h) = 42 m

Acceleration due to gravity (g) = 10 m/s²

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The potential energy can be obtained as follow:

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PE = 12 × 10 × 42

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KE = ½ × 1500 × 10²

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