Question

A balloon with a charge of 6.0 μC is held a distance of 0.80 m from a second balloon having the same charge. Calculate the magnitude of the repulsive force.

Answer 1

Answer:0.506 N

Explanation:

Given

Charge on first balloon $q_1=6\ \mu C$

Charge on second balloon is $q_2=6\ \mu C$

Distance between them $r=0.8\ m$

Electrostatic Repulsive force is given by

$F=\dfrac{kq_1q_2}{r^2}$

Where K is constant

$F=\dfrac{9\times 10^9\times 6\times 10^{-6}\times 6\times 10^{-6}}{(0.8)^2}$

$F=\dfrac{324\times 10^{-3}}{0.64}$

$F=0.506\ N$