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lions [1.4K]
3 years ago
12

A balloon with a charge of 6.0 μC is held a distance of 0.80 m from a second balloon having the same charge. Calculate the magni

tude of the repulsive force.
Physics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:0.506 N

Explanation:

Given

Charge on first balloon q_1=6\ \mu C

Charge on second balloon is q_2=6\ \mu C

Distance between them r=0.8\ m

Electrostatic Repulsive force is given by

F=\dfrac{kq_1q_2}{r^2}

Where K is constant

F=\dfrac{9\times 10^9\times 6\times 10^{-6}\times 6\times 10^{-6}}{(0.8)^2}

F=\dfrac{324\times 10^{-3}}{0.64}

F=0.506\ N

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