Answer:
Inappropriate practice is conduct by a practitioner in connection with rendering or initiating services that a practitioner's peers could reasonably conclude was unacceptable to the general body of their profession.
Explanation:
Answer:
ΔV = 78 V
Explanation:
The potential at a point due to a point charge is given as:
where,
V = Potential at the point
k = Colomb's Constant = 9 x 10⁹ Nm²/C²
q = charge = 3.25 x 10⁻⁹ C
r = distance
AT POINT A:
AT POINT B:
Now, the potential difference will be:
<u>ΔV = 78 V</u>
Answer:
The reason is to allow the thermometer to respond relatively quickly, and relatively accurately. The glass contains the liquid being used in the thermometer, but if it is too thick, then it will not pass heat as quickly, and it will absorb some of the heat from whatever is being measured.
Explanation:
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Answer:
Vy = 0
y(max) = 137,76 m
x(max) = 318 m
Explanation:
We are dealing with a projectile movement
And from problem statement we know:
θ = 60⁰ then sin θ = sin 60⁰ = √3/2 and cos 60⁰ = 1/2 and g = 9.8 m/sec²
V₀ = 60 m/sec
V₀x = V₀ *cosθ Vx = V₀x Vx = Constant then Vx = V₀ *cosθ
Then Vx = 60* 1/2 Vx = 30 m/sec
V₀y = V₀ *sinθ ⇒ V₀y =60*√3/2 ⇒ V₀y = = 30*√3 m/sec
Vy = V₀y * sin θ - g*t
When Vy = 0 (maximum height point) we are half of the way for the ball to hit the ground, then
Vy = 0 ⇒ V₀y - g*t = 0 ⇒ 30*√3 (m /sec) = 9,8 (m/sec²)* t
t = 30*√3/9.8 t = 5.30 sec
y(max) = y₀ + V₀y*t - 1/2 * g*t²
By substitution:
y (max) = 0 + 30*√3 * 5.30 - 0,5* 9.8* (5.3)²
y(max) = 275,40 - 137,64
y(max) = 137,76 m
And finally x(max)
x(max) = Vx *t = 30* 2*5,3
x(max) = 318 m
To solve this question you need to find the time span of the ski jumper before he lands
thus
25 = 1/2*10*t^2
50/10 = t^2
t = 2.23 seconds
and the distance is given 135m
speed = distance/time
= 135/2.23
= 60.5 m/s