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Vera_Pavlovna [14]
3 years ago
11

The speed of a tennis ball that is served is 73.14 m/s. During a serve, the ball typically starts from rest and is in contact wi

th the tennis racquet for 30 milliseconds. Assuming constant acceleration, what is the average force exerted on the tennis ball during the serve, expressed in terms of the ball’s weight w?
450w
150w
250w
350w
Physics
1 answer:
Serga [27]3 years ago
3 0

Answer: Third option

F = 250w

Explanation:

The impulse can be written as the product of force for the time interval in which it is applied.

I = F (t_2-t_1)

You can also write impulse I as the change of the linear momentum of the ball

I = mv_2 -mv_1

So:

F (t_2-t_1) = mv_2 -mv_1

We want to find the force applied to the ball. We know that

(t_2-t_1) = 30 milliseconds = 0.03 seconds

The initial velocity v_1 is zero.

The final speed v_2 = 73.14\ m / s

So

F * 0.03 = 73.14m

F * 0.03 = 73.14m\\\\F=\frac{73.14m}{0.03}\\\\F=2438m

We must express the result of the force in terms of the weight of the ball.

We divide the expression between the acceleration of gravity

g = 9.8\ m / s ^ 2

F=\frac{2438m*g}{g},\ \ m*g=w\\\\g=9.8\ m/s^2\\\\F=\frac{2438w}{9.8}\\\\F=249w

The answer is the third option

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