Answer:
1/3 the distance from the fulcrum
Explanation:
On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:
where
W1 is the weight of the boy
d1 is its distance from the fulcrum
W2 is the weight of his partner
d2 is the distance of the partner from the fulcrum
In this problem, we know that the boy is three times as heavy as his partner, so
If we substitute this into the equation, we find:
and by simplifying:
which means that the boy sits at 1/3 the distance from the fulcrum.
I'm assuming it was to keep the data consistent? The further you are from a heat source the less heat will get to you as the temperature tries to reach equilibrium and the waves start to spread out, so you should keep everything the same distance to get consistent results. I don't have any information so this is just my assumption
Force of a crate : 300 N
<h3>Further explanation</h3>
Given
0.25 meters wide and 1.5 meters long
Pressure = 800 Pa
Required
Force
Solution
P = F/A
A = 0.25 x 1.5
A = 0.375 m²
P = 800 Pa = 800 N/m²
Input the value :
F = P x A
F = 800 N/m² x 0.375 m²
F = 300 N
Answer:
3.53*10^{-7} m
Explanation:
Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:
Hence, we have
but the energy is also:
where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:
hope this helps!
Answer:
Solution given:
velocity=40cm/s
wave length=5cm
we have
frequency =velocity/wavelength=40/5=8hertz.
the frequency of the <u>wave</u><u> </u><u>i</u><u>s</u><u> </u><u>8</u><u> </u><u>h</u><u>e</u><u>r</u><u>t</u><u>z</u><u>.</u>
