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adelina 88 [10]
3 years ago
15

A sled is being pulled along a horizontal surface by a horizontal force F of magnitude 600 N. Starting from rest, the sled speed

s up with acceleration 0.08 m/s^2 for 1 minute. Find the average power P created by force F.
Physics
1 answer:
Simora [160]3 years ago
6 0

Answer:

1440 W

Explanation:

First of all, we can find the total displacement of the sled, which is given by

d=\frac{1}{2}at^2

where

a = 0.08 m/s^2 is the acceleration

t = 1 min = 60 s is the time

Substituting,

d=\frac{1}{2}(0.08 m/s^2)(60 s)^2=144 m

Now we can find the wotk done on the sled, equal to the product between force and displacement:

W=Fd=(600 N)(144 m)=86,400 J

And finally we can fidn the average power, which is the ratio between the work done and the time taken:

P=\frac{W}{t}=\frac{86,400 J}{60 s}=1440 W

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Given Information:

Diameter of spherical cell = 0.040 mm

thickness = L = 9 nm

Resistivity =  ρ = 3.6×10⁷ Ω⋅m

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Answer:

time constant = 2.87×10⁻³ seconds

Explanation:

The time constant is given by

τ = RC

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We know that resistivity of of any material is given by

ρ = RA/L

R =  ρL/A

Where area of spherical cell is given by

A = 4πr²

A = 4π(d/2)²

A = 4π(0.040×10⁻³/2)²

A = 5.026×10⁻⁹ m²

The resistance becomes

R =  (3.6×10⁷*9×10⁻⁹)/5.026×10⁻⁹

R = 6.45×10⁷ Ω

The capacitance of the cell membrane is given by

C = kεoA/L

Where k = 9 is the dielectric constant and εo = 8.854×10⁻¹² F/m

C = (9*8.854×10⁻¹²*5.026×10⁻⁹)/9×10⁻⁹

C = 44.5 pF

C = 44.5×10⁻¹² F

Therefore, the time constant is

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τ = 6.45×10⁷*44.5×10⁻¹²

τ = 2.87×10⁻³ seconds

6 0
3 years ago
please solve this for me ,A garden roller is pulled with a force of 200N acting at an angle of 50 degree with the ground level.f
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Answer:

The force pulling the roller along the ground is 128.55 N

Explanation:

A force of 200 N acting at an angle of 50° with the ground level

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The force that pulling the roller along the ground is the horizontal

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→ The force acting is 200 N at direction 50° with ground (horizontal)

→ The horizontal component = F cosФ

→ F = 200 N , Ф = 50

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128.55 N is the horizontal component of the force that pulling the

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<em>The force pulling the roller along the ground is 128.55 N</em>

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Answer:

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3 0
3 years ago
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