A sled is being pulled along a horizontal surface by a horizontal force F of magnitude 600 N. Starting from rest, the sled speed
1 answer:
Answer:
1440 W
Explanation:
First of all, we can find the total displacement of the sled, which is given by
where
a = 0.08 m/s^2 is the acceleration
t = 1 min = 60 s is the time
Substituting,
Now we can find the wotk done on the sled, equal to the product between force and displacement:
And finally we can fidn the average power, which is the ratio between the work done and the time taken:
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5.3 km
This question involves continuous displacement in various directions. When it becomes difficult to imagine, vector analysis becomes handy.
Let us denote each of the individual displacements by a vector. Consider the unit vectors as the unit vectors in the direction of East and North respectively.
By simple calculations, we can derive the unit vectors j, and in the directions North, South of West, and North of West respectively.
So Total displacement vector = The Sum of individual displacement vectors.
Displacement vector = -4.25i + 3.165j
The magnitude of Displacement =| -4.25i + 3.165j | = 5.3km
∴ Total displacement = 5.3km
A displacement is a vector in geometry and mechanics that have a length equal to the shortest distance between a point P's initial and final positions. It measures the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement.
The final location xf of a point relative to its beginning position xi, or a relative position (derived from the motion), is another way to express a displacement. The difference between the final and initial coordinates can be used to define the equivalent displacement vector.
To learn more about displacement from the given link:
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<u>Answer:</u> The final temperature of the mixture is 45.6°C
<u>Explanation:</u>
To calculate the mass of water, we use the equation:
Density of water = 1 g/mL
- <u>When volume is 240.0 mL</u>
Putting values in above equation, we get:
- <u>When volume is 100.0 mL</u>
Putting values in above equation, we get:
When two water solutions at different temperature are mixed, the amount of heat released by water present at higher temperature will be equal to the amount of heat absorbed by water present at lower temperature..
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of water solution 1 = 240 g
= mass of water solution 2 = 100 g
= final temperature = ?°C
= initial temperature of water solution 1 = 25°C
= initial temperature of water solution 2 = 95°C
c = specific heat of water= 4.186 J/g°C
Putting values in equation 1, we get:
Hence, the final temperature of the mixture is 45.6°C