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Dvinal [7]
3 years ago
11

How could you increase the power of a wave in a spring

Chemistry
1 answer:
krok68 [10]3 years ago
4 0

Answer:

Supply All Kinds of Springs

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Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you
oee [108]

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

\eta_{KClO_{3}} = \frac{m}{M}

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

\eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles                                      

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

\eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles

Finally, the mass of O₂ is:

m = 0.378 moles*32 g/mol = 12.10 g

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

6 0
3 years ago
PLEASE HELP!!
sp2606 [1]
Inbox me for the answer

6 0
3 years ago
when a chemical change occurs, what do you know about the amount of matter in the new substances? what is this known as?( is it
Pavel [41]

Explanation:

The law of conservation of mass states that the total mass of the products is equal to the total of the reactants.

A chemical change occurs because of a chemical reaction.

In a chemical reaction, the reactants are the starting substances and the products is the finishing substances. The amount of each type of atoms to start with and end with are also equal.

No matter disappears after a chemical reaction.

Answer:

The amount of matter in the new substances is the same as the original.

This is known as the law of conservation of mass.

6 0
3 years ago
How many liters of 4M solution can be made using 100 grams of lithium bromide
uysha [10]
Molar mass of LiBr (mm )= 86.845 g/mol

Molarity ( M ) = 4 M 

Mass of solute ( m ) = 100 g

Volume ( V ) = in liters ?

V = m / mm  * M

V = 100 / 86.845 * 4

V = 100 / 347.38

V = 0.2875 L

hope this helps!.
5 0
3 years ago
After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 mill
IRINA_888 [86]
A is obviously out because it leads to a volume of 125.0 milliliters of the new solution and gives you a lower concentration than you were aiming for.

D is out because you are adding 75 milliliters of the stock solution, so your concentration would be too high. You only need 25.0 milometers of stock solution per 100 milliliters of the new solution.

C is also out because it leads to 50.0 milliliters stock solution per 100 milliliters of the new solution and hence the wrong concentration.

B is by default the correct answer. It also details the correct technique. First you add the stock solution (This you know from your calculations to be 25 milliliters.) then you add the water up to the volume you needed. (Because the calculations only tell you the total volume of water not what you need to add) You also add the water last so you can rinse the neck of the flask to make sure you also get all the stock solution residue into the stock solution.

I would add the final step of stirring, but B is the only answer that can be correct.
8 0
3 years ago
Read 2 more answers
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