<h3>
Answer:</h3>
30 m/s
<h3>
Explanation:</h3>
<u>We are given:</u>
Initial Velocity (u) = 0 m/s
Acceleration of the Car (a) = 3 m/s²
Time Interval (t) = 10 seconds
<u>Speed of the Car After 10 seconds:</u>
From the First equation of motion:
v = u + at
replacing the given values
v = 0 + (3)(10)
v = 30 m/s
Hence, the car is moving at a velocity of 30 m/s after 10 seconds
Work input is something done with a simple machine.
Output is the same except the use more compound machines with less force.
Hi!
Mechanical advantage is defined as the<em> ratio of force produced by an object to the force that is applied to it.</em>
In our case, this would be the ratio of the force applied by the claw hammer on the nail to the force Joel applies to the claw hammer, which is
160:40 or 4:1
So the mechanical advantage of the hammer is four.
Hope this helps!
Is is the second one. 336 k. 273.15K= 0C.
Answer:
0.546 ![\hat k](https://tex.z-dn.net/?f=%5Chat%20k)
Explanation:
From the given information:
The force on a given current-carrying conductor is:
![F = I ( \L \limits ^ {\to } \times B ^{\to})\\ \\ dF = I(dL\limits ^ {\to } \times B ^{\to})](https://tex.z-dn.net/?f=F%20%3D%20I%20%28%20%5CL%20%20%5Climits%20%5E%20%7B%5Cto%20%7D%20%5Ctimes%20B%20%5E%7B%5Cto%7D%29%5C%5C%20%5C%5C%20dF%20%3D%20I%28dL%5Climits%20%5E%20%7B%5Cto%20%7D%20%5Ctimes%20B%20%5E%7B%5Cto%7D%29)
where the length usually in negative (x) direction can be computed as
![\L ^ {\to } = -x\hat i \\dL\limits ^ {\to }- dx\hat i](https://tex.z-dn.net/?f=%5CL%20%5E%20%7B%5Cto%20%7D%20%20%3D%20-x%5Chat%20i%20%5C%5CdL%5Climits%20%5E%20%7B%5Cto%20%7D-%20dx%5Chat%20i)
Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:
![\int dF = \int ^3_1 I ( dL^{\to} \times B ^{\to})](https://tex.z-dn.net/?f=%5Cint%20dF%20%3D%20%5Cint%20%5E3_1%20I%20%28%20dL%5E%7B%5Cto%7D%20%5Ctimes%20B%20%5E%7B%5Cto%7D%29)
![F = I \int^3_1 ( -dx \hat i ) \times ( 4.0 \hat i + 9.0 \ x^2 \hat j)](https://tex.z-dn.net/?f=F%20%3D%20I%20%5Cint%5E3_1%20%28%20-dx%20%5Chat%20i%20%29%20%5Ctimes%20%28%204.0%20%5Chat%20i%20%2B%209.0%20%5C%20x%5E2%20%5Chat%20j%29)
![F = I \int^3_1 - 9.0x^2 \ dx \hat k](https://tex.z-dn.net/?f=F%20%3D%20I%20%5Cint%5E3_1%20%20-%209.0x%5E2%20%5C%20dx%20%5Chat%20k)
![F = I (9.0) \bigg [\dfrac{x^3}{3} \bigg ] ^3_1 \hat k](https://tex.z-dn.net/?f=F%20%3D%20I%20%20%289.0%29%20%5Cbigg%20%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%20%5Cbigg%20%5D%20%5E3_1%20%5Chat%20k)
![F = I (9.0) \bigg [\dfrac{3^3}{3} - \dfrac{1^3}{3} \bigg ] \hat k](https://tex.z-dn.net/?f=F%20%3D%20I%20%20%289.0%29%20%5Cbigg%20%5B%5Cdfrac%7B3%5E3%7D%7B3%7D%20-%20%5Cdfrac%7B1%5E3%7D%7B3%7D%20%5Cbigg%20%5D%20%20%5Chat%20k)
where;
current I = 7.0 A
![F = (7.0 \ A) (9.0) \bigg [\dfrac{27}{3} - \dfrac{1}{3} \bigg ] \hat k](https://tex.z-dn.net/?f=F%20%3D%20%287.0%20%5C%20A%29%20%20%289.0%29%20%5Cbigg%20%5B%5Cdfrac%7B27%7D%7B3%7D%20-%20%5Cdfrac%7B1%7D%7B3%7D%20%5Cbigg%20%5D%20%20%5Chat%20k)
![F = (7.0 \ A) (9.0) \bigg [\dfrac{26}{3} \bigg ] \hat k](https://tex.z-dn.net/?f=F%20%3D%20%287.0%20%5C%20A%29%20%20%289.0%29%20%5Cbigg%20%5B%5Cdfrac%7B26%7D%7B3%7D%20%5Cbigg%20%5D%20%20%5Chat%20k)
F = 546 × 10⁻³ T/mT ![\hat k](https://tex.z-dn.net/?f=%5Chat%20k)
F = 0.546 ![\hat k](https://tex.z-dn.net/?f=%5Chat%20k)