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irga5000 [103]
3 years ago
13

Two convex lenses with focal lengths 10.0 cm and 20.0 cm are separated by 70.0 cm. An object is located at 15.0 cm to the left o

f the first lens. Use the equation to calculate q1, P2, q2, M1 and M2 as measured from the second lens, then describe the final image?
Physics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

Explanation:

Let us consider image formation from first mirror

object distance u = - 15 cm

v = ?

f = 10 cm

1 / v - 1 / u = 1 / f

1 / v + 1 / 15 = 1 / 10

1 / v = 1 / 10 - 1 / 15

= .1 - .067

= .033

v = 30 cm

Magnification M1 = v / u = - 30 / 15 = - 2

This image will act as object for second mirror

object distance for second mirror

u = 70 - 30 = 40 cm

f = 20 cm

v = ?

1 / v - 1 / u = 1 / f

1 / v + 1 / 40 = 1 / 20

1 / v = 1 / 20 - 1 / 40

= .05 - .025

= .025

v = 40 cm

Magnification M2 = v / u

= - 40 / 40

= -1 .

overall magnification

M = M1 X M2

= -2 x -1

= + 2

Final image will be 2 times the object and it will be real and it will be erect with respect to object .

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goldfiish [28.3K]

Answer:

center of mass of the two masses will lie at x = 2.52 cm

center of gravity of the two masses will lie at x = 2.52 cm

So center of mass is same as center of gravity because value of gravity is constant here

Explanation:

Position of centre of mass is given as

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here we have

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r_1 = (0, 0)

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r_g_{cm} = (2.52 cm, 0)

So center of mass is same as center of gravity because value of gravity is constant here

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