All categories

3 years ago

A 0.500 kg mass is oscillating on a

Physics

1 answer:

drek231 [11]3 years ago

7 0

Answer:

3.6m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5Kg

Spring constant (K) = 330N/m

Energy = 3.24J

Velocity (v) =..?

The velocity of the mass can be obtained as follow:

E = ½mv²

3.24 = ½ × 0.5 × v²

3.24 = 0.25 × v²

Divide both side by 0.25

v² = 3.24/0.25

Take the square root of both side

v = √(3.24/0.25)

v = 3.6m/s

Therefore, the speed of the mass is 3.6m/s

You might be interested in

An airplane flying parallel to the ground undergoes two consecutive displacements. The first is 50 km 60.0° west of north, and t

Rashid [163]

Answer:

LOL

Explanation:

IMAGINE POSTING UR CLASSWORK LOLL

8 0

2 years ago

You are looking down on a N = 9 turn coil in a magnetic field B = 0.5 T which points directly down into the screen. If the diame

Novay_Z [31]

Answer:

The magnitude of the voltage is $2.27\times10^{-4}\ V$ and the direction of the current is clockwise.

Explanation:

Given that,

Number of turns = 9

Magnetic field = 0.5 T

Diameter = 3 cm

Time t = 0.14 s

We need to calculate the flux

Using formula of flux

$\phi=NAB$

Put the value into the formula

$\phi=9\times\pi\times(1.5\times10^{-2})^2\times0.5$

$\phi=0.003180$

We need to calculate the emf

Using formula of emf

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{0.003180}{0.14}$

$\epsilon =-0.000227\ V$

$\epsilon=-2.27\times10^{-4}\ V$

Negative sign shows the direction of current.

Hence, The magnitude of the voltage is $2.27\times10^{-4}\ V$ and the direction of the current is clockwise.

8 0

3 years ago

As a city planner, you receive complaints from local residents about the safety of nearby roads and streets. One complaint conce

WINSTONCH [101]

Answer:

a) x₁ = 290.50 feet , x₂ = 169.74 feet , b) v_max= 41 mph

Explanation:

For this exercise we will work in two parts, the first with Newton's second law to find the acceleration of vehicles

X Axis fr = m a

Y Axis N-W = 0

N = W = mg

The force of friction has the expression

fr = μ N

We replace

μ mg = ma

a = μ g

g = 32 feet / s²

Let's calculate the acceleration for each coefficient and friction

μ a (feet / s2)

0.599 19.168

0.536 17,152

0.480 15.360

0.350 11.200

These are the acceleration values, for the maximum distance we use the minimum acceleration (a₁ = 11,200 feet / s²) and for the minimum braking distance we use the maximum acceleration (x₂ = 19,168 feet / s²)

v² = v₀² - 2 a x

When the speed stops it is zero

x₁ = v₀² / 2 a₁

Let's reduce speed

v₀ = 55mph (5280 foot / 1 mile) (1h / 3600s) = 80,667 feet / s²

Let's calculate the maximum braking distance

x₁ = 80.667² / (2 11.2)

x₁ = 290.50 feet

The minimum braking distance

x₂ = 80.667² / (2 19.168)

x₂ = 169.74 feet

b) maximum speed to stop at distance x = 155 feet

0 = v₀² - 2 a x

v₀ = √2 a x

We calculate the speed for the two accelerations

v₀₁ = √ (2 11.2 155)

v₀₁ = 58.92 feet / s

v₀₂ = √ (2 19.168 155)

v₀₂ = 77.08 feet / s

To stop at the distance limit in the worst case the maximum speed must be 58.92 feet / s = 40.85 mph = 41 mph

5 0

3 years ago

How can we maximise the rate of energy transfer to keep things cool?

faltersainse [42]

To do this we may use things that are good conductors - are painted dull black -
Have a air flow around them Maximised.

6 0

3 years ago

Weight=1500n area=0.5 m2 pressure=

Dmitriy789 [7]

Answer: 6000N/m^2

Explanation:

Weight =1500N

Area =0.5m^2

Pressure =1500/(0.5^2)

=6000N/m^2

Note: Newton is denoted by 'N' (Capital) and use '^' for powers.

8 0

2 years ago