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Oksanka [162]
3 years ago
13

A 0.500 kg mass is oscillating on a

Physics
1 answer:
drek231 [11]3 years ago
7 0

Answer:

3.6m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 0.5Kg

Spring constant (K) = 330N/m

Energy = 3.24J

Velocity (v) =..?

The velocity of the mass can be obtained as follow:

E = ½mv²

3.24 = ½ × 0.5 × v²

3.24 = 0.25 × v²

Divide both side by 0.25

v² = 3.24/0.25

Take the square root of both side

v = √(3.24/0.25)

v = 3.6m/s

Therefore, the speed of the mass is 3.6m/s

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Lena is studying the properties of light in a laboratory. If she increases the amplitude of the light waves she is studying, wha
zaharov [31]

Answer:

A brighter light

Explanation:

Light waves travel through space via light particles called photons. This particles have in essence 2 properties: 1. Amplitude and 2.Frequency. The first one has to do with the intensity of light we see and the second one has to do with the energy (color). If we change only the amplitude, we will see a lighter or darker light and will keep the same color in all amplitude changes. But if we modify the frequency, the intensity will keep the same and the color changes as we move into the light spectrum.

Thus, increasing the amplitude, we will perceive a brigher light.

4 0
3 years ago
you have been provided with an insulated wire , voltmeter or a battery with a charge of 10ohms, a bulb, a switch and a resistor
eduard
I’m trying to get my points up I have the same question
4 0
3 years ago
A 75 kg football player is gliding forward across very smooth ice at 4.6 m/s. He throws a 0.47 kg football straight forward. A)
lord [1]

Answer:

4.53482 m/s

4.506 m/s

Explanation:

m_1 = Mass of player = 75 kg

v_1 = Initial velocity of player = 4.6 m/s

m_2 = Mass of ball = 0.47 kg

v_1 = Initial velocity of ball = 15 m/s

The linear momentum of the system is conserved

(m_1+m_2)v_1=m_1v+m_2v_2\\\Rightarrow v=\dfrac{(m_1+m_2)v_1-m_2v_2}{m_1}\\\Rightarrow v=\dfrac{(75+0.47)4.6-0.47\times 15}{75}\\\Rightarrow v=4.53482\ m/s

The player's speed is 4.53482 m/s

In the second case the equation of momentum is

(m_1+m_2)v_1=m_1v+m_2(v_2+v_1)\\\Rightarrow v=\dfrac{(m_1+m_2)v_1-m_2(v_2+v_1)}{m_1}\\\Rightarrow v=\dfrac{(75+0.47)4.6-0.47\times (15+4.6)}{75}\\\Rightarrow v=4.506\ m/s

The player's speed is 4.506 m/s

4 0
4 years ago
Please help
natali 33 [55]

Answer:

Thermosphere

temperature continue to rise up to 1500*C

Ionosphere

Mesosphere

temperature falls to -93*C

Stratosphere

protective ozone layer

UV radiation causes temperature to rise

Troposphere

78% nitrogen, 21% oxygen

temperature drops from 17 to -52*C

Explanation:

3 0
3 years ago
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the
ExtremeBDS [4]

Answer:

a) v_{0y} = 9.72 m/s

b) v_{0x} = 20.85 m/s

c) t = 2.01 s

d) h_{max} = 4.82 m

Explanation:

a) The initial vertical velocity is given by:

v_{0y} = v*sin(\theta)

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

v_{0y} = 23 m/s*sin(25) = 9.72 m/s

b) The initial horizontal velocity can be calculated as follows:

v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s

c) The flight time can be calculated using the following equation:

v_{0x} = \frac{x}{t}

Where:

x: is the total distance = 42 m

t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s

d) The maximum height is given by:

v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}

Where:

v_{fy}: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m

I hope it helps you!                                  

7 0
3 years ago
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